What is the cutoff of NSIT Delhi?

NSUT Delhi (Formerly NSIT Delhi) Cutoff 2019

Round	Branch	Max JEE(M) Rank
1	Computer Engineering	1121
1	Computer Science and Engineering with specialization in Artificial lntelligence	871
1	Electrical Engineering	4092
1	Electronics and Communication Engineering	2854

What is the cutoff of nsit 2020?

NSUT Delhi (Formerly NSIT Delhi) Cutoff 2020

Round	Branch	Max JEE(M) Rank
1	Information Technology	7174
1	Information Technology with specialization in Network and Information Security	8976
1	Instrumentation and Control Engineering	29041
1	Manufacturing Processes and Automation Engineering	32497

What is the eligibility criteria for BTech at NSIT Delhi?

What is the eligibility criteria for B.Tech at NSIT Delhi? Ans. The candidate must have scored a minimum of 75\% marks ( 65\% marks for SC/ST) in 10+2 to be eligible. He/she must have also compulsorily studied Physics, Chemistry, Mathematics/Biotechnology.

What happens after the Nsit 2020 cutoff marks are released?

After the release of the cutoff marks of NSIT 2020, all the shortlisted candidates will have to attend the counselling round. Those allotted courses of their choice will further have to go for admission. They need to carry the prescribed documents for verification and pay the admission fees for confirmation of seat.

How do I get admission in NSUT Delhi for a BBA?

For selection, the candidate has to take the JEE- Main. NSUT Delhi offers a three-year BBA program in three specializations, namely, Marketing, Finance, and Human Resources. Admissions to the program are done through Common Management Admission Committee (CMAC), Delhi.

What is the cut off rank for Computer Science at NSIT?

Previous Years’ NSIT Cutoff rank Branch General SC ST Computer Engineering (COE) 2336 52469 135008 Computer Science and Artificial Intellig 1868 33393 118677 Information Technology (IT) 6546 101330 239723 Electronics and Communication Engineerin 13693 143192 364807

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