How will you compare the range of a projectile fired at 30 and 60 angles?

Answer: B Explanation: A careful inspection of either Figure 1 or Table 1 reveals that the range of a projectile has an identical value for more than one launch angle. For instance, the range is the same for a 15° and a 75° angle. The range is also the same for a 30° and a 60° launch angle.

Why does 30 degrees and 60 degrees have the same range?

An object thrown up into the air at 60 degrees will have the same horizontal distance (or range) as if it were thrown at 30 degrees. An object moving upward slows down due to gravity and an object moving downward speeds up due to gravity. The speed lost while going up equals the speed gained while going down.

How do you find the range of a projectile angle?

As illustrated by the figure, the larger the initial launch angle and maximum height, the longer the flight time of the object. Projectile Trajectories: The launch angle determines the range and maximum height that an object will experience after being launched.

What is height of a projectile?

Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point – and it’s falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0).

How do you calculate the maximum height of a projectile?

hmax = h – initial height from which we’re launching the object is the maximum height in projectile motion. Just relax and look how easy-to-use this maximum height calculator is: Choose the velocity of the projectile. Let’s type 30 ft/s. Enter the angle.

What is the velocity of the body projected at 30o with the horizontal?

A body is projected with the velocity of 60 m/s at an angle of 30o with the horizontal. Find a) the maximum height reached by the body, b) the time of flight, c) horizontal range

How do you calculate the time of flight of a projectile?

Calculate the time of flight. Flight ends when the projectile hits the ground. We can say that it happens when the vertical distance from the ground is equal to 0. In the case where the initial height is 0, the formula can be written as: Vy * t – g * t² / 2 = 0.

What is the distance traveled by a projectile being affected by gravity?

The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v 2 /g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity. Assuming that v 2 /g is constant, the greatest distance will be when sin(2θ) is at its maximum, which is when 2θ = 90 degrees.