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Does the Point 2 StartRoot 6 EndRoot lie on the circle shown?

Does the Point 2 StartRoot 6 EndRoot lie on the circle shown?

Does the point (2,root of 6) lie on the circle shown? Explain. No, the distance from (0, 0) to (2, root of 6) is not 3 units. Does the point (1, StartRoot 7 EndRoot) lie on the circle shown?

Which equation represents a circle that contains the Point 2 8 and has a center at 4 0 )?

Equation x2 + y2 – 8x – 84 = 0 represents a circle that contains the point (-2, 8) and has a center at (4, 0).

Which circle is tangent to the x-axis and the Y-axis?

A circle with center (-2,1) is tangent to the y-axis. What is the radius, equation, and is the circle also tangent to the x-axis? It is tangent to the y-axis, therefore, the y-axis is perpendicular to the radius. A radius and the y-axis intersects at (0,1) and this point is 2 units away from the center. Have a nice day !!! from the Philippines..

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How to find the equation of a circle given center and tangent?

How To Find the equation of a circle given: center & tangent. Now, from the center of the circle, measure the perpendicular distance to the tangent line. This gives us the radius of the circle. Using the center point and the radius, you can find the equation of the circle using the general circle formula (x-h)* (x-h) + (y-k)* (y-k) = r*r,…

What is the standard form of the circle equation?

Standard form of circle equation is (x – a) 2 + (y – b) 2 = r 2 Substituting the values of centre and radius, (x – 2) 2 + (y – 3) 2 = 1 2 x 2 – 4x + 4 + y 2 – 6y + 9 = 1

How to find the equation of a circle?

How To Find the equation of a circle given: center & tangent. This gives us the radius of the circle. Using the center point and the radius, you can find the equation of the circle using the general circle formula (x-h)* (x-h) + (y-k)* (y-k) = r*r, where (h,k) is the center of your circle and r is the radius.