Questions

Why is the derivative of a constant always zero?

Why is the derivative of a constant always zero?

Since the derivative is the slope of the function at any given point, then the slope of a constant function is always 0. Hence, the derivative of a constant function is always 0.

Why is the derivative of any horizontal line always zero?

The slope of any horizontal line is zero. Since the graph of any constant function is a horizontal line like this, the derivative is always zero.

What happens when derivative is zero?

Note: when the derivative curve is equal to zero, the original function must be at a critical point, that is, the curve is changing from increasing to decreasing or visa versa.

Why is the derivative of a function always 0?

The derivative represents the change of a function at any given time. The constant never changes—it is constant. Thus, the derivative will always be 0. Consider the function x2 −3. It is the same as the function x2 except that it’s been shifted down 3 units. The functions increase at exactly the same rate, just in a slightly different location.

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How do you prove that a constant is a derivative?

This is property is very easy to prove using the definition provided you recall that we can factor a constant out of a limit. Here’s the work for this property. This is very easy to prove using the definition of the derivative so define f (x) = c f ( x) = c and the use the definition of the derivative.

Is the Newton quotient already zero before h → 0?

The ” x 0 ” really plays no role; besides, it is 1 and any other constant works with the same proof. f ( x + h) − f ( x) h = c − c h = 0. So, the Newton quotient is already zero before taking the limit as h → 0. I had the same question, in an effort to understand the essence of the rule.

Why is the derivative of x2 the same as x2?

The constant never changes—it is constant. Thus, the derivative will always be 0. Consider the function x2 −3. It is the same as the function x2 except that it’s been shifted down 3 units. The functions increase at exactly the same rate, just in a slightly different location. Thus, their derivatives are the same—both 2x.