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Why integration of COSX is Sinx?

Why integration of COSX is Sinx?

Before evaluating the integral of sin x cos x, let us recall the trigonometric formula which consists of sin x cos x, which is sin 2x = 2 sin x cos x. Integration is the reverse process of differentiation, and hence the integration of sin x cos x is also called the anti-derivative of sin x cos x.

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Why is the integral of sqrt(1-cosx) from 0 to 2pi 0?

What I don’t understand is why is the integral of sqrt (1-cosx) from 0 to 2pi equals 0? Unless otherwise specified, “sqrt” indicates the nonnegative square root, and in that case, the answer should definitely be greater than zero. 1-cos is never negative and usually positive, so by integrating its square root, you’ll get a positive value.

What is cos 2x = 1 – 2sin2(X)?

Using the cosine double angle formula cos(2x) = 1 − 2sin2(x), we also see that cos(x) = 1 − 2sin2( x 2): This is a special integral, namely the incomplete elliptic of the second kind E. It is defined by E(φ ∣ k2) = ∫ φ 0 √1 − k2sin2(θ)dθ.

Can the square root of 1-cos be negative?

Unless otherwise specified, “sqrt” indicates the nonnegative square root, and in that case, the answer should definitely be greater than zero. 1-cos is never negative and usually positive, so by integrating its square root, you’ll get a positive value. Therefore, something went wrong in the method where you got 0.