Why binding energy of vanadium is greater than chromium Although chromium has more unpaired electrons?

Cr has six unpaired electrons but due to stable electron configuration (3d5 4S1) do not want to lose electron. As the 3d orbital is half filled, therefore, the melting point of Vanadium is higher than Cr.

Why do the transition metals have higher enthalpy of atomization?

The valence electrons result in the formation of strong metallic bonds between the transition metals. As the metallic bonds are stronger, a higher amount of energy is required to break the bonds between the transition metals. Thus, the enthalpy of atomization of transition metals is higher.

Which element has highest enthalpy of atomization in 3d series?

Answer: Vanadium have the highest atomisartion enthalpy.

Which of the following transition metals has the highest enthalpy of atomisation?

Now with increasing the bond strength , higher will be the energy required for atomization. In case of Mn due to the highest number of unpaired electrons the atomization energy for Mn is also highest. On the other hand, in case of Zn due to all paired d electrons the atomization energy is least for Zn.

Which of the following pair of elements has highest and least enthalpy of atomization respectively among 3d series elements?

In the 3 d series from Sc (z = 21) to Zn (z = 30) , enthalpy of atomisation of Zn is the lowest.

Which transition element has highest enthalpy of atomisation?

Is chromium more reactive than vanadium?

However, Cr can attain the higher oxidation state, at which point it becomes more reactive as Cr+5 and Cr+6 , forming the +VI and +VII oxidation states, respectively.

How does vanadium have the highest atomization enthalpy instead of chromium?

How does vanadium, having only 3 unpaired electrons, have the highest atomization enthalpy instead of chromium which has 6 unpaired electron? The Rock reveals the key to success for normal people. The big companies don’t want you to know his secrets. i see people confuse here. dont fully try to compare enthalpy of atomization to melting point.

What happens when you remove electrons from vanadium(0)?

So, what that does mean is that if you remove electrons from vanadium(0), you will remove the $\\mathrm{4s}$electrons before you remove the $\\mathrm{3d}$-electrons. So, you have the following electronic configurations:

What is the electron configuration of vanadium?

I know that the electron configuration of vanadium is $[\\ce{Ar}]\\mathrm{4s^2 3d^3}$. None of the electrons in the 3d subshell are paired. Once it loses these three electrons, shouldn’t the remaind…

What is enthalpy of atomization?

Enthalpy of atomization is referred to as the amount of energy required in breaking mettalic lattice to generate free atoms. Cr [ 3d^5 4s^1] contains the maximum number of unpaired electrons ( six), but this configuration has EXTRA STABILITY due to its having HALF FILLED d-sub shell which makes it to have MAXIMUM EXCHANGE ENERGY.