What is the sum of the 100 odd numbers?
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What is the sum of the 100 odd numbers?
The number series 1, 3, 5, 7, 9, . . . . , 199. Therefore, 10000 is the sum of first 100 odd numbers.
How do you find the average of 100 odd numbers?
The average is given by the formula: Average = sum of the observations/number of observations. Average = sum of odd numbers up to 100 / 100 = 5000/100 = 50.
How do you find the 100th odd number?
The fourth odd number would be 5 + 2, or 7. The fifth odd number would be 7 + 2, or 9. So, we see that the i th odd number is obtained by adding i-1 to i which is the same as 2i – 1. Therefore, the 100th odd number is 2(100) – 1 or 199.
What is the average of five consecutive odd numbers?
The average of any five consecutive odd numbers is the third number of the sequence (in this case, c). You can prove this by setting a equal to c-4, b = c-2, d= c+2, and e= c+4. Add those four numbers together with c, and the sum of the five numbers is 5c. Divide that sum by 5 to get the average of the five numbers, which is c.
How to find the average of a series of consecutive numbers?
First you need to add the two values in parentheses. Then divide by 2. The result will be the average of the series of numbers. For example: (15+45)2=602=30{\\displaystyle {\\frac {(15+45)}{2}}={\\frac {60}{2}}=30}. So, the average of the series of consecutive numbers beginning with 15 and ending with 45 is 30.
What is the lowest number in this set of odd numbers?
The average (62 in this case) of an odd number of consecutive numbers is the middle number of the set. That means this set begins at four even numbers below 62 and ends at four even numbers above 62. Therefore, the lowest number in this set is 54.
How do you find the median and mean of a series?
For example, in the sequence 3, 4, 5, 6, 7, 8, 9, the middle number is 6. It has three numbers to the left of it, and three numbers to the right of it. So, in this series of numbers, 6 is both the mean and the median. Average the middle numbers of a series with an even number of terms.