What is the solution of sin x?

Hence, the general solution for sin x = 0 will be, x = nπ, where n∈I. Similarly, general solution for cos x = 0 will be x = (2n+1)π/2, n∈I, as cos x has a value equal to 0 at π/2, 3π/2, 5π/2, -7π/2, -11π/2 etc.

How many solutions exist for x sin x?

…… The solutions of above equations are infinitely many, so there are infinite number of solutions with x³=0 as one among them. So, x=0 is the solution of sinx=x and also many other solutions.

What is cos 2x in terms of sin?

Cos2x In Terms of sin x Now, that we have derived cos2x = cos2x – sin2x, we will derive the formula for cos2x in terms of sine function only. We will use the trigonometry identity cos2x + sin2x = 1 to prove that cos2x = 1 – 2sin2x. We have, cos2x = cos2x – sin2x.

What is cos x -sin2x = 0?

For example, cos x -sin 2 x = 0, is a trigonometric equation which does not satisfy all the values of x. Hence for such equations, we have to find the values of x or find the solution. We know that sin x and cos x repeat themselves after an interval of 2π, and tan x repeats itself after an interval of π.

What is the general solution for sin x = 0?

But, we know that if sin x = 0, then x = 0, π, 2π, π, -2π, -6π, etc. are solutions of the given equation. Hence general solution for sin x = 0 will be, x = nπ, where n∈I.

How to solve cos2(x)?

Move cos2(x). Apply pythagorean identity. Rewrite √22 as 2. Tap for more steps… Rewrite √ 2 as 2 1 2. Apply the power rule and multiply exponents, ( a m) n = a m n. Combine 1 2 and 2. Cancel the common factor of 2. Tap for more steps… Cancel the common factor. Divide 1 by 1. Evaluate the exponent. Simplify each term. Tap for more steps…

How do you find the sine function of 2x?

Divide each term in 2 x = π 2 by 2. Cancel the common factor of 2. Tap for more steps… Cancel the common factor. Divide x by 1. Multiply π 2 ⋅ 1 2. Tap for more steps… Multiply π 2 and 1 2. Multiply 2 by 2. The sine function is positive in the first and second quadrants.