Guidelines

What is the lowest rank in JEE Advanced?

What is the lowest rank in JEE Advanced?

JEE Main 2020 Cut Off for JEE Advanced

Category Cutoff
Common Rank List (CRL) 89.7548849
Economically Weaker Section (EWS) 78.2174869
Other Backward Class (OBC-NCL) 74.3166557
Scheduled Caste (SC) 54.0128155

What rank is required for JEE Advanced 2020?

To appear for JEE Advanced 2020, the minimum requirement for general & OBC is 75\% and 65\% score for SC, ST & PwD in 12th or equivalent. Also, to qualify for JEE Advance 2020 you must be among the 2,24,000 rank holder.

What is the JEE Advanced 2020 marks vs rank analysis?

JEE Advanced marks vs rank will enable IIT aspirants to predict their admission possibilities. It will further help IIT aspirants to predict their rank and eligible colleges based on the marks that they score in the JEE Advanced exam. A lot of students are curious to know the JEE Advanced 2020 marks vs rank analysis.

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How to get a good rank(under Air 500) in the JEE Main?

Both are equally important for getting a good score. How to Get a Good Rank (Under AIR 500) in the JEE Main and JEE Advanced? Here are some tips to get a good rank in JEE. Study with concentration. It is always better to study 1 hour with full concentration than studying 2 hours while watching TV.

How many JEE Advanced students did not take coaching?

Interestingly, various studies and analysis of the JEE Advanced results suggest that as many as 35 to 50 per cent students who qualify the examination did not take coaching. In 2019, Aditya Kumar from Bihar not only cracked JEE Main, he also cracked NEET, AIIMS and IISc Bangalore’s admission test – all without coaching.

How can I get a Top 100 rank in IIT JEE?

You need to aim at 100\% knowledge index for every potential topic or question to be able to get a top 100 rank in IIT JEE. Speed and accuracy – Only an intensive and planned study plan will yield the desired score and rank. There is an abundance of numerical problems in IIT JEE papers so candidate must be adept at solving numerical problems.