What is the general solution of COSX?
What is the general solution of COSX?
Similarly, general solution for cos x = 0 will be x = (2n+1)π/2, n∈I, as cos x has a value equal to 0 at π/2, 3π/2, 5π/2, -7π/2, -11π/2 etc….Solutions for Trigonometric Equations.
| Equations | Solutions |
|---|---|
| cos x = 0 | x = (nπ + π/2) |
| tan x = 0 | x = nπ |
| sin x = 1 | x = (2nπ + π/2) = (4n+1)π/2 |
| cos x = 1 | x = 2nπ |
How many solutions does Sinx 2 have?
The range of sine is −1≤y≤1 – 1 ≤ y ≤ 1 . Since 2 does not fall in this range, there is no solution.
What is the solution to Sinx 2?
Is there any solution for the equation sin x = 2? The answer is yes if you accept complex numbers. However, the reader should know a bit of complex numbers and trigonometry….Equation.
| Equation | Solutions |
|---|---|
| sin x = -2 | – 1.5708 ± 1.31696 i |
| sin x = i | ± 0.881374 i |
What is the solution to SiNx+cosx=3/2?
Which is not possible because both sinx and cosx has range of -1 to 1. What is the solution to sinx+cosx=3/2? There is no solution in the real numbers. This is because Which is clearly impossible as the range of \\sin (x) is abs (\\sin (x))<1. However, if we allow complex numbers, then there are infinitely many solutions.
How many solutions of \\sin(x) are there?
Which is clearly impossible as the range of \\sin (x) is abs (\\sin (x))<1. However, if we allow complex numbers, then there are infinitely many solutions. We start off with the sine of a complex number, which is
Why does the equation have no solution if x is zero?
For the equation the maximum and minimum value of can be found of from the expression: So for the given function we get the maximum and minimum value as and respectively. And as so the equation will never be satisfied irrespective of any value of x, hence the equation has no solution.
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