What is the formula for relativistic mass?

In special relativity, the relativistic mass is given by m = γm0, where γ = 1/ √(1 − v2/c2) and c is the speed of light in a vacuum (299,792.458 km [186,282.397 miles] per second). Then the corresponding formulas for p and E, respectively, are p = mv and E = mc2.

Where m0 is the rest mass of the particle and c is the speed of light in a vacuum find the inverse function of F and explain its meaning?

where m0 is the rest mass of the particle and c is the speed of light in a vacuum. Find the inverse function of f and explain its meaning. √ 1 − v2/c2 = m0 m .

How do you find the relativistic mass of a photon?

If you take Einstein’s equation E = m c^2 , where m = mass and c = speed of light, and the Planck equation for the energy of a photon, E = h f , where h = Planck’s constant and f = the frequency of the photon, and combine them you get: m c^2 = hf or that m = h f/c^2.

What is M m0?

In the theory of relativity, the mass of a particle with velocity v is. m = m0.

What is the inverse of the theory of relativity?

So the meaning of the inverse function is that the speed of an object as a function of its relativistic mass is given as above. For example, when mass is twice the rest mass, we see a speed of 0.867 of the speed of light!

Does relativistic mass really exist?

There is no such thing, What you call “relativistic mass” is just the sum of an object’s rest mass and its (relativistic) kinetic energy.

How are photons massless?

If there was a way (there isn’t; special relativity prohibits it) to observe a photon at rest, you would find it massless. All the relativistic mass of the photon comes from it’s energy. This is why we usually say that photons are massless.

Is relativistic mass real — Quora?

Relativistic mass is a mathematical theory in relation to an observers perspective. It is not a reality, it also has nothing to do with the misconception that nothing can go at or faster than the speed of light.

What is the mass of a photon at rest?

The rest mass of a photon is equal to zero. Indeed, that’s also the reason why one can’t really have a photon at rest, $v=0$. If a speed of something is $c$ in one reference frame, it will stay $c$ in any (non-singular) reference frame – that’s another postulate of the special theory of relativity.

Why can’t massless photons have momentum?

This is given as a solution to the problem of only massive objects being affected by gravity. However, momentum is the product of mass and velocity, so, by this definition, massless photons cannot have momentum.

How to calculate the momentum of a photon with m = 0?

Once m2 = E2 − p2 is established, it follows trivially that for a photon, with m = 0, E = | p |, i.e., p = E / c in units with c ≠ 1. A lot of the confusion on this topic seems to arise from people assuming that p = mγv should be the definition of momentum. It really isn’t an appropriate definition of momentum,…

Is it possible to make the speed of a photon zero?

If a speed of something is $c$ in one reference frame, it will stay $c$ in any (non-singular) reference frame – that’s another postulate of the special theory of relativity. So one can’t ever make the speed of the photon zero by switching to another (non-singular) reference frame.