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What is the empirical formula of a molecule with 80\% of carbon and 20\% of hydrogen?

What is the empirical formula of a molecule with 80\% of carbon and 20\% of hydrogen?

And thus moles of carbon≡80⋅g12.011⋅g⋅mol−1=6.66⋅mol . And thus moles of hydrogen≡20⋅g1.008⋅g⋅mol−1=19.8⋅mol . Clearly, n=2 , and the MOLECULAR FORMULA is C2H6 .

What is the empirical formula of a compound containing 85.7\% C and 14.3\% H if the compound has a molar mass of 84.0 g mol What is the molecular formula?

empirical formula = CH2 .

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Which one of the following is the molecular formula of a hydrocarbon containing 80\% by mass of carbon?

And thus the simplest molecular formula is that of ethane, (CH3)×2=C2H6 .

What are the empirical and molecular formulas of a compound that contain 86.88\% carbon and 13.12\% hydrogen and has a molar mass of 345 g?

C4H5N2O
The empirical formula is C4H5N2O. A compound contains 86.88\% of carbon and 13.12\% of hydrogen, and the molecular weight is 345.

What information is needed to calculate the percent composition of a compound?

The equation for percent composition is (mass of element/molecular mass) x 100. Find the molar mass of all the elements in the compound in grams per mole.

What is the percentage of oxygen O by mass in sodium bicarbonate?

The mass percent of oxygen in sodium bicarbonate (NaHCO3) is 57.13\% Oxygen.

What is the relative molecular mass of a hydrocarbon?

A hydrocarbon contains carbon and hydrogen. 85.7\% of carbon is present in a given hydrocarbon. Its relative molecular mass is 70g/mol. What is the empirical formula of the compound?

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What is the percentage of hydrogen in hydhydrocarbon?

Hydrocarbon contains 18.18\% hydrogen and 81.82\% carbon. One litre of this gas has the same mass as carbon dioxide. What is the molecular formula of this hydrocarbon? | Socratic

What is the atomic mass of hydrogen in empirical formula?

Atomic mass of hydrogen: Measured as 1.008 correspond to 17.34/1.008 = 17.202 atoms of hydrogen. “A compound is made of 82.66\% carbon and 17.34\% hydrogen. What is its empirical formula?” Since 82.66 + 17.34 = 100.00, this compound is a hydrocarbon, with no other element present.

What percentage of carbon is present in a gaseous hydrocarbon?

A gaseous hydrocarbon contains 82.76 \% of carbon. Given that its vapour density is 29, find its molecular formula. [C = 12,H =1]. . Was this answer helpful?