What is the balanced equation for the combustion of butane c4h10?

C4H10 + O2 → CO2 + H2O .

What is the coefficient for o2 when the equation for the combustion of c4h10 is balanced?

8
The coefficient of CO2 is 8 .

What is the balanced equation for C3H8 o2 CO2 h2o?

The final equation will be C3H8 + 502 —-> 3CO2 + 4H20.

What is the coefficient of CO2?

The diffusion coefficients of CO2 and HCO3- of 100\% hemolysate were 0.34 X 10(-5) and 0.14 X 10(-5) cm2/sec, respectively.

What is the coefficient for H2O?

2
Because each water molecule, H2O, contains only one oxygen atom, two water molecules must form for each oxygen molecule that reacts. The coefficient 2 in front of the H2O(l ) makes this clear.

How do you balance C4H10 + O2 = CO2 + H2O?

In order to balance C4H10 + O2 = CO2 + H2O you’ll need to watch out for two things. First, be sure to count all of C, H, and O atoms on each side of the chemical equation. Once you know how many of each type of atom you have you can only change the coefficients (the numbers in front of atoms or compounds) in order to balance the equation.

What is the unbalanced equation for the combustion of butane?

We have the unbalanced equation: This is the combustion of butane, C4H 10. Let’s first balance the carbons. There are four on the LHS, but only one on the RHS, so we multiply CO2 by 4 to get: Now, let’s balance the hydrogens. There are 10 on the left side, but only two on the right side, so we multiply H 2O by 5, and get:

How do you find the scale number of H2O?

There are 10 on the left side, but only two on the right side, so we multiply H 2O by 5, and get: Final step is to balance the oxygens. There are two on the left hand side, but thirteen on the right hand side, so we need to divide thirteen by two to get the “scale number”, which is 6.5. The equation is thus:

How do you balance hydrogens and oxygens?

Now, let’s balance the hydrogens. There are 10 on the left side, but only two on the right side, so we multiply H 2O by 5, and get: Final step is to balance the oxygens. There are two on the left hand side, but thirteen on the right hand side, so we need to divide thirteen by two to get the “scale number”, which is 6.5.