What happens to the volume of a cone when the radius and height are tripled?

If you triple the radius of a cone, given the formula of the volume of a cone: , assuming the height stays constant, then the volume of the cone will increase by a factor of 9. Question: What happens if you triple the radius of a cone? The area of the base would be multiplied by 9.

What happens to the volume of a cone if the height and also the radius are doubled?

Let the radius and height of the cone be r and h respectively. If the radius r is doubled it becomes 2r. Hence the volume of the cone will become 4 the original volume when the radius is doubled height remaining the same.

How many percentage of the volume of a right circular cone will be increased or decreased if its radius of the base is increased by 20\% and height is decreased by 10\%?

It is given that the base radius and the height are increased by 20\%. So now the base radius is ‘1.2r’ and the height is ‘1.2h’. Hence the percentage increase in the volume of the cone is 72.8\%, which is approximately equal to 73\%.

When the radius of a cone tripled the volume is?

If the radius of a cone is tripled, the volume of the cone is how many times larger? Therefore, the new cone is 9 times larger.

How does volume of cone change with height?

The volume of a cone of radius r and height h is given by V = 1/3 pi r^2 h. If the radius and the height both increase at a constant rate of 1/2 cm per second, at what rate in cubic cm per sec, is the volume increasing when the height is 9 cm and the radius is 6 cm.

What is the percentage increase formula?

To calculate a percentage increase, first work out the difference (increase) between the two numbers you are comparing: Increase = New Number – Original Number. Next, divide the increase by the original number and multiply the answer by 100: \% increase = Increase ÷ Original Number × 100.

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