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What happens to the spacing of the fringes if you increase or decrease the slit separation?

What happens to the spacing of the fringes if you increase or decrease the slit separation?

The spacings between different fringes decreases as the distance between the slits increases because it is dependent on L. Increasing the wavelength of the light increases the spacing between different fringes since the spacing between different fringes is wavelength dependent.

What happens to the fringe spacing when the wavelength of light is decreased?

From the equation, we can tell that the fringe width is directly proportional to the wavelength. Therefore, decreasing the wavelength of the light causes the fringe spacing to also decrease. If the wavelength of the light is decreased, the fringe spacing also decreases.

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What will happen if the distance between the two slits in Young’s double slit experiment is increased?

When the slits are narrow, any light that passes through them, bends at the corners, hence suffer diffraction. As a result there is considerable overlap of the diffraction patterns and hence wide fringes are observed. But, if the width of slits are increased, most light pass through the slits undiffracted.

How does the fringe width in Young’s double slit experiment change when the distance of separation between the slits and screen is doubled?

How does the fringe width, in Young’s double-slit experiment, change when the distance of separation between the slits and screen is doubled? Answer: Fringe width, β=Dλ/d When the distance D between the slits and the screen is doubled, the fringe width also gets doubled.

What happens if you increase slit spacing?

As the slit separation increased, the fringe width decreased, meaning there was less interference. Also, as the distance between the slits and the wall increased, the fringe width increased, because the light would have more space to diffract outwards, and thus be able to interfere more.

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What happens when you increase the distance between slit and screen?

Yes, if the distance between two slits is increased then the width of fringe will increase. The amplitude should be proportional to the width. In single slit diffraction calculations, the resultant amplitude is obtained by dividing the slit width into a large number of equal segments.

How does slit width affect fringe separation?

The separation of the interference fringes depends on the slit separation. If now the slit width is increased the width of the diffraction envelope is decreased whilst the separation of the interference fringes stays the same. So less interference fringes will be visible.

Why the fringe separation is proportional to wavelength of light used?

Intuitively speaking, the reason behind this is that for creating the same phase difference for light with larger wavelength, the path difference needs to be more than that for light with a shorter wavelength, so the fringe width would be more for a larger wavelength.

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What happens when distance between slits is doubled?

Fringe width y=λD2d ,2d = separation between the slits D = distance between screen and slits λ=wavelength of incident light wave. Hence fringe width will become 4 times the earlier width.

How does the fringe width?

Fringe width, β = Dλ/d => β ∝ λ for same D and d. When the whole apparatus is immersed in a transparent liquid of refractive index n =1×3, the wavelength decreases to λ = λ/n = λ/1.3. so, fringe width decreases to 1/1.3 time.