What happens to the interference pattern if the two slits s1 and s2?

No interference pattern will be observed on the screen. The two slits in Young’s double slit experiment are illuminated by two different sodium lamps emitting light of the same wavelength. No interference pattern will be observed on the screen.

What happens to the interference pattern when one of the slits is closed?

If one of the two slits is closed, the interference pattern disappears. If two independent sources are used instead of coherent sources coming from single source, then interference pattern is not permanent and positions of bright and dark fringe do not remain fixed.

What happens when destructive interference occurs?

Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is cancelled exactly by a negative displacement of the other wave. The amplitude of the resulting wave is zero. The dark regions occur whenever the waves destructively interfere.

Does the double slit experiment show wave function collapse in reality?

There are so many videos showing the actual double slit experiment but none show the actual wave function collapse in reality when the particles are “observed”.

Is there a detector that can detect interference in a double slit?

I thought you were asking about the detector downstream of the double slit, where the interference pattern is visible; every practical double-slit experiment includes such a detector. But instead you are asking about a hypothetical detector which could “tag” a particle as having gone through one slit or the other.

Does the double-slit experiment contain the heart of quantum mechanics?

“Richard Feynman famously said that ‘the double-slit experiment has in it the heart of quantum mechanics. In reality, it contains the only mystery. 4 ‘ Therefore, a more complete understanding there will be useful in all areas where interference is considered a resource.

What is the problem with the three alternatives to superposition?

The problem is that the three alternatives (slits A and B, slit A, slit B) correspond to separate boundary conditions – equations that specify the behavior of the solution to a system of differential equations at the boundary of that system’s domain – meaning that superposition does not apply.