What happens to the force if q1 is doubled?
Table of Contents
- 1 What happens to the force if q1 is doubled?
- 2 What must be the relation between charges q1 and q2?
- 3 How does the force of gravitation between two objects change when the distance between them is reduced to half Byjus?
- 4 What is the relation between charges Q1 and q2 and Q3?
- 5 What is the value of Ke if two charges are doubled?
What happens to the force if q1 is doubled?
Hence, the force becomes 4 times its initial value. If both charges are doubled then referring to the above equation we come up with the conclusion that the force would be quadrupled. It will quadruple.
What happens to force when charge is doubled?
Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.
What happens to the force between the two charges if the distance between them is quadrupled?
Therefore, as the separation distance between the charges increases, the electric force between the charges decrease.
What must be the relation between charges q1 and q2?
If the charges q1 and q2 are of the same sign (both positive or both negative) then the force is mutually repulsive and the force on each charge points away from the other charge.
How can the electric force between two charges q1 and q2 be doubled?
Justification: The electric force one charge exerts on another is directly proportional to the product of the two charges, and thus is also proportional to each individual charge. If the magnitude of one charge is doubled then the magnitude of the force is also doubled.
What is the force applied between q1 and q2?
q2 is positive (in case of like charges), the force F is positive and pushes the charges away from each other. The product q1. q2 is negative for unlike charges and the force F is negative. This means the objects are attracted to each other.
How does the force of gravitation between two objects change when the distance between them is reduced to half Byjus?
When the distance between the two objects is halved, the gravitational force becomes four times.
What happens to the force of one charge is doubled and the distance is doubled?
The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.
Which of the two charges Q1 and q2 is greater in magnitude?
From the graph, it can be seen that net potential due to the two charges is positive everywhere in the region left of charge Q1. Therefore, the magnitude of potential due to charge Q1 is greater than that due to Q2. Therefore, the absolute value of charge Q1 is greater than that of Q2.
What is the relation between charges Q1 and q2 and Q3?
Answer: Q1 is the “middle” value in the first half of the rank-ordered data set. Q2 is the median value in the set. Q3 is the “middle” value in the second half of the rank-ordered data set.
When each of the two charges is doubled the force also doubles?
The force between them is proportional to the product of the charges. If one charge doubles, then their product doubles. So, if the distance between them doesn’t change, then the force also doubles. When each of the two charges is doubled the force between them also doubled?
What happens if you double the force between Q1 and Q2?
If q1 is doubled leaving q2 unchanged, F is doubled. If q2 is doubled leaving q1 unchanged, F is doubled. If both q1 and q2 are doubled leaving the distance between them unchanged, the magnitude of the force F is quadrupled.
What is the value of Ke if two charges are doubled?
Where (F) is the force acting simultaneously on both point charges (q1) and (q2). r is the separation distance and ke is a proportionality constant called the Coulomb constant. Using above equation, if we double both charges and reduce the distance in half. │F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.
How do you calculate Q1 and Q2 charges?
A point charge of 12.00 x 10 -9 C is 15m distant from a second point charge of 6.80 x 10 -9 C. Calculate the magnitude of the electrostatic force on each charge. Q1 = 12.00 x 10 -9 C. Q2 = 6.80 x 10 -9 C.