Is the sum of four consecutive numbers always even?

We can now call our four consecutive numbers x, x+1, x+2, x+3. So, when we ‘sum’ these 4 numbers we get; x + (x+1) + (x+2) + (x+3) = (x+x+x+x) + (1+2+3) = 4x + 6. If we look carefully at ‘4x + 6’, we should be able to factorise this quite easily.

How do you write four consecutive even numbers?

Therefore, the first even number x =82, the second even number (x + 2) = 82 + 2 = 84, the third even number (x + 4) = 82 + 4 = 86 and the fourth even number (x + 6) = 82 + 6 = 88. Thus, the four consecutive even numbers whose sum is equal to 356 are, 82, 84, 86 and 88.

What are four consecutive whole numbers that have a sum of 2022?

The sum of these numbers is indeed 504 + 505 + 506 + 507 = 2022. Therefore, the four consecutive numbers are 504, 505, 506, and 507.

What is the sum of the consecutive even integers?

The sum of the consecutive even integers is 212; Now that we have those facts, let’s start representing our four consecutive even integers. Let {2k} be the first even integer. The four even integers are consecutive, which means that the second even integer must be the first even integer increased by 2 or {2k+2}.

What is the second consecutive integer of 14 14?

14 14. Write all the elements of the set. 14 14 is the smallest. 14 14 has the least value, it must be the first element of the set of consecutive even integers. 2 2 to it. Thus, \\color {blue}14 + 2 = 16 14 + 2 = 16 is the second consecutive integer. 2 2 again. That is, \\color {blue}16 + 2 = 18 16 + 2 = 18.

How many consecutive even integers are 2 units apart?

1 We will ADD four even integers that are consecutive 2 The numbers are 2 units apart from each other 3 Each integer is 2 more than the previous integer 4 The sum of the consecutive even integers is 2 1 2 212 212

What is the second consecutive even integer 2k+2k +2?

2k 2k be the first even integer. The second consecutive even integer is 2 2 units more than the first. Thus, 2k + 2 2k + 2 is the second consecutive even integer. 66 66, we should have a setup just like the one below.