How many words can be made from the letters of the word permutations so that all the five vowels in it are together?

They can be arranged among themselves in 5! = 120 ways. Hence, the number of arrangements in which 5 vowels are together=(20160×120)=2419200.

How many different ways can the letter of the word Leading be arranged in such a way that the vowels always come together?

Solution(By Examveda Team) The word ‘LEADING’ has 7 different letters. When the vowels EAI are always together, they can be supposed to form one letter. Then, we have to arrange the letters LNDG (EAI). Now, 5 (4 + 1 = 5) letters can be arranged in 5!

How many sequences are possible in the word assassination?

Alan P. Treat each of the 8 letters of “assassin” as if they were unique (perhaps by thinking of them as being different colors). There would be 8! ways of doing this.

How many different ways can the letters of the word permutation can be arranged?

In how many ways can the letters of the word “PERMUTATIONS” be arranged so that there are always 4 letters between ‘P’ and ‘S’? There should always be 4 letters between P and S. Therefore, total number of permutations = 14 × 1814400 =25401600.

How many different ways can the letters Leading be arranged?

 Required number of ways = (120 x 6) = 720. The word ‘LEADING’ has 7 different letters. When the vowels EAI are always together, they can be supposed to form one letter. Then, we have to arrange the letters LNDG (EAI).

How many different ways can the alphabet of the word Leading be arranged?

when the vowels EAI are always together , they can be supposed to form one letter. then , we have to arrange the letters LNDG (EAI) . Now , 5(4+1=5) letters can be arranged in 5! = 120 ways .

How many permutations of the word “permutations” are there?

In how many ways can the letters of the word “PERMUTATIONS” be arranged so that there are always 4 letters between ‘P’ and ‘S’? There should always be 4 letters between P and S. Therefore, total number of permutations = 14 × 1814400 =25401600.

How do you arrange permutations such that P comes before s?

So, the ways to arrange “Permutations” such that p comes before s will be comb (12,2)×fact (10)/fact (2). Total places required to write this word is 12. Lets fix the place for “p” and “s” such that p comes before s and move rest of 10 places.

What is the total number of permutations of 1814400?

There should always be 4 letters between P and S. Therefore, total number of permutations = 14 × 1814400 =25401600. Was this answer helpful? Thank you. Your Feedback will Help us Serve you better.

How many arrangements are there in the word P E Rm u?

Hence, required number of arrangements = 2!10! ii) There are total 12 letters in the word P E RM U T AT I ON S, with T repeated twice. Number of vowels in the given word are 5. Since vowels have to always occur together, so they are considered as a single object .