How many ways can 5 boys and 3 girls be seated in a row?

Ways. Thus we have arranged 5 boys and 3 girls in 14400 ways in such a way that no 2 girls are together.

What is the number of ways that 4 boys and 3 girls can be seated so that boys and girls sits alternate?

×3! =1202=60 ways. Now, from the fundamental principle of multiplication, we can say that the number of ways in which 4 girls and 3 boys be seated in a row so that no two boys are together will be equal to m×n=24×60=1440 ways. Thus, the required number of ways will be 1440 ways.

How many ways can 3 boys be seated in 8 seats?

Thus there are a total of 6* [ (2*5)+ (5*4)] = 180 ways for 3 boys to be seated in the row of 8 seats in accordance with the constraints of having 2 boys seated together and the 3rd boy separated from either of the pair seated together. The 5 girls can then be seated in 5! ways in the 5 remaining seats.

How many ways can 5 boys & 3 girls be arranged?

5 boys & 3 girls are sitting in a row of 8 seats. Number of ways in which they can be seated so that not all the girls sit side by side, is? Total no of ways they can be arranged is without any restrictions = 8! ways.

How many seats are there to fill 8 persons?

There are 8 seats to be filled with 8 persons (girls and boys). The number of boys and girls is immaterial unless it’s specified that they need to be seated together or any other constraints exist. In the absence of additional constraints, and so on… I’ve thought of several ways of doing this.

How many pairs of girls can sit in adjacent seats?

Two pairs of girls sit in adjacent seats: Since there are only three girls, this can only occur if the three girls sit in consecutive seats. We have six objects to arrange, the block of three girls and the five boys. The objects can be arranged in 6! ways.