How many ways can 10 people be arranged in a circle?

But there are 10 possible such points. So there are 10 ways of seating 10 people abreast for every way of seating them at a round table. It follows that the number of ways of seating 10 people at a round table = 10!/10 = 9! = 362,880.

How many ways can 10 different?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

How many ways can 10 people be selected 3?

120
How many ways can one choose a committee of 3 out of 10 people? ) = 120.

How many ways can 10 students be arranged?

This is because each student can be seated in any of the 10 seats. So, there could be 3628800 possible arrangements. In 10!(= 10×9×8×7×6×5×4×3×2×1) ways.

How many ways can 10 people be paired?

In particular we get for ten people that there are 945 arrangements (fifth term in the sequence with m=5 and five pairs for 10 people in total).

How many ways are there to select 5 players from 10 members?

252
5! Therefore, the number of ways of selecting a committee of 5 members from a group of 10 persons is 252.

How many ways can you pick 3 students from 10 students?

Combination: Choosing 3 desserts from a menu of 10. C(10,3) = 120. Permutation: Listing your 3 favorite desserts, in order, from a menu of 10. P(10,3) = 720.

How many ways can you pick 10 players to take the field?

Answer: a) 3003 ways to choose 10 players to take the field.

How many ways can you pick 4 students from 10 students?

10*9*8*7 = 5040. So there is 5040 ways to pick 4 people from a starting pool of 10.

How many ways can 1010 students be arranged in a row?

10 students can be arranged in a row in 10! ways.this is because each student can be seated in any of the 10 seats.There could be 3628800 possible arrangements. 3,628,800. If you mean arranging the students in different orders, the answer has to be 3,628,800 different ways.

How many ways 8 people can be seated around a table?

The two persons who insist on sitting next to each other can be seated in 2 different ways. The remaining 6 plus 1 group of the two persons = 7 entities can be arranged in a circular fashion in (7–1)! =6! ways. Hence total no of ways 8 persons can be seated around a round table such that 2 given persons are seated next to each other = 2*6! = 1440.

How many permutations can two people arrange among themselves?

Again, two as one entity can also arrange among themselves in 2 ways. Therefore, required arrangement = 4! x 2 = 24 x 2 = 48 ways. (b) Among the 5 boys, total number of permutations will be = 5! = 120. The arrangement in which two boys are always together is 48 ways. The remaining in no two boys are never together will be = 120 – 48 = 72 ways.

How many different arrangements can you make with 10 seats?

Pick one of 10 people to fill a seat. Now pick one of the remaining 9 people to fill the next seat clockwise, and so on. That makes 10⋅9⋅…⋅2⋅1=10! different arrangements in all. But there are 10 arrangements in each equivalence class, which you can get by rotating an arrangement by 0 to 9 seats. (If you rotate it by 10 seats it’s the same again.)