How many ways a project team of 5 members can be selected from 6 men and 5 women consisting of 3 men and 2 women?

(∵ncr=n! r! (n−r)!) Hence in a committee of 5 members selected from 6 men and 5 women consisting 3 men and 2 women is 200 ways.

How many ways can a committee be formed of 5 members from 6 men and 4 women?

A committee of 5 out of 6 + 4= 10 can be made in 10C5 = 252 ways.

How many different committees of 5 can be formed from 6 men and 4 women on which accept 3 men and 2 women serve?

Originally Answered: A committee of 5 persons is to be formed from 6 men and 4 women. How many ways can this be done when at most, 2 women are included? So in total there are 186 possibilities.

How many ways can a team of 5 members be formed by 6 boys and 4 girls if at least 2 girls should be selected?

Hence, the required number of ways =(120+60+6)=186.

How many ways can a committee of 5 persons be formed out of 6 men and 4 women when at least one woman has to be necessarily selected?

Therefore, the total number of ways the committee can be formed is = (120 + 60) = 180 ways.

How many committees of 5 members can be formed?

5! Therefore, the number of ways of selecting a committee of 5 members from a group of 10 persons is 252.

How many different committees consisting 3 males and 2 females may be formed from 6 males and 6 females?

There are 1,176 different possible committees.

How many possible sub-groups of only men are there?

Of the 8 men available, we must choose 3. The number of possible groups is 8C3, which is 8! 3! × 5! = 56. Of the 7 women available, we must choose 2. The number of possible groups is 7C2, which is 7! 2! × 5! = 21. Finally, each of the 56 possible sub-groups of only men could be paired with each of the 21 possible sub-groups of only women.

How to calculate the number of ways to select men?

Approach: Since, we have to take at least k men. Totals ways = Ways when ‘k’ men are selected + Ways when ‘k+1’ men are selected + … + when ‘n’ men are selected . // This code is contributed by 29AjayKumar.

What is the combination of 4 men and 3 women?

Combinations of these 3 women that include A = 56–35 = 21. Combinations of 4 men and 3 women that include neither D nor A = 5*35 = 175. Combinations of 4 men and 3 women that include D but not A = 10*35 =350. Combinations of 4 men and 3 women that include A but not D = 21*5 = 105.

How many men and women are needed to form a committee?

A committee of 5 persons is to be formed from 6 men and 4 women. In how many ways can this be done when at least 2 women are included? Originally Answered: A committee of 5 is to be formed out of 6 gents and 4 ladies. In how many ways can this be done when at most, two ladies are included?

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