How many passwords can you make with 4 characters?
Table of Contents
- 1 How many passwords can you make with 4 characters?
- 2 How many possibilities are there with 4 numbers and letters?
- 3 How many characters are there in a 14-character password?
- 4 What is the number of passwords with 1 letter and 3 digits?
- 5 What is the maximum possible permutations of Part Two of the password?
How many passwords can you make with 4 characters?
i.e. 456,967 solutions means that those many number of alphabet combinations can be made ( including repetitions ) to form 4 letter words.
How many possibilities are there with 4 numbers and letters?
If we assume your letters range from A to Z and your digits from 0 to 9, you have 26 possibilities per letter and 10 per digit. This gives you 26^4*10^4 which is roughly 4 billion and a half. I would say – without much thinking – 26^4 * 10000, if the order is given: 4 letters and 4 digits.
What characters are allowed in passwords?
Passwords should contain three of the four character types:
- Uppercase letters: A-Z.
- Lowercase letters: a-z.
- Numbers: 0-9.
- Symbols: ~`! @#$\%^&*()_-+={[}]|\:;”‘<,>.?/
How many characters are there in a 14-character password?
The hacker knows (somehow) that the password is 14 characters long, and that each character is either a lowercase letter, (a, b, c, etc), an uppercase letter (A, B, C, etc) or a How many 6-letter words can be made from the letters WASTEFUL if repetition of letters is allowed? A computer password is required to be 9 characters long.
What is the number of passwords with 1 letter and 3 digits?
Thanks to the comment I received from Mr Alan Klette, I realized that I had not paid sufficient attention to the wording of the question. The correct answers are: Passwords with 1 letter and 3 digits: 26 (letters of the alphabet of the english language)*10^3 (three integers, each 0 to 9)=26000.
How many numbers are there in 26000 passwords?
The correct answers are: Passwords with 1 letter and 3 digits: 26 (letters of the alphabet of the english language)*10^3 (three integers, each 0 to 9)=26000. Passwords with 1 letter and 4 digits:26* (10^4)=260000. Passwords with 3 or 4 digits: 26000 + 260000=286000.
What is the maximum possible permutations of Part Two of the password?
We have ten digits to choose from, and four places in which to put them. 10^4 is 10,000, but you can’t quite get there – you can only get to 9,999. This means that the maximum possible permutations of part two of the password is 9,999.