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How many numbers from 0 to 999 are divisible by either 5 or 7?

How many numbers from 0 to 999 are divisible by either 5 or 7?

So there are 142 + 199 – 28 = 313 numbers divisible by 5 or 7 in the given set of numbers from 0 to 999. The other numbers are not divisible by either 5 or 7. There are 1000 – 313 = 687 such numbers. The required number of numbers not divisible by 5 or 7 in the set of numbers from 0 to 999 is 687.

What are all the multiples of 5 and 7?

LCM of 5 and 7 is the smallest number among all common multiples of 5 and 7. The first few multiples of 5 and 7 are (5, 10, 15, 20, 25, 30, 35, . . . ) and (7, 14, 21, 28, 35, . . . ) respectively.

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What are the first multiples of 5 and 7?

How to list multiples of a number?

Multiples of 1 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, …
Multiples of 5 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, …
Multiples of 6 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, …
Multiples of 7 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, …
Multiples of 8 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, …

How many numbers are there between 1 and 999?

We know that there are 2889 digits needed to write down all the numbers from 1 to 999. If we continue from here writing down the numbers up to 9999, we have 9000 numbers, each requiring 4 digits, so the number of digits needed to write all the numbers from 1 up to 999 is 2889 + 4 × 9 × 1000.

How many numbers are there between 1 and 800 that are divisible by 5 or 7 but not by 35?

How many numbers are there which are divisible by neither 5 nor 7, in the set {200, 201, 202, ….., 798, 799, 800}? Because total numbers in the given set are : (800 – 200) + 1 = 601. Since we have calculated number of numbers which are divisible by either 5 or 7 or both in just earlier question : (121 + 86) – 17 = 190.

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What is the GCF of 5 and 7?

1
Answer: GCF of 5 and 7 is 1.

How many numbers between 1 and 1000 contain the digit 5?

300 times
Hence, the digit 5 appears 300 times from 1 to 1000.

What is the greatest multiple of 7*5 and 999?

You should find the greatest multiple of 7*5=35 that’s inferior to 999. in other word you should find an integer n such as n*35 is an integer inferior to 999. That number is 35*27, so in addition to zero as a multiple of 35, you have 28 multiples of 5 and 7.

How many multiples of 12 are there between 100 and 999?

A number to be divisible by both 3 and 4 should be divisible by the least common multiple of 3 and 4 so by 12. # of multiples of 12 between 100 and 999, inclusive is (last-first)/multiple+1= (996-108)/12+1=75 (check this: how-many-multiples-of-4-are-there-between-12-and-94862. How many positive integers are there between 100 and 999?

How many numbers are both multiples of 5 and 7?

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First find a common factor all those numbers has. Since 5 and 7 are both prime numbers, multiply them together to get 35. So then divide 999 by 35 that will tell you how many numbers are both multiples of 5 and 7 because 35 is the first multiple and all other multiples have to be multiples of 35

How do you find the multiples of a number?

Calculator Use The multiples of numbers calculator will find 100 multiples of a positive integer. For example, the multiples of 3 are calculated 3×1, 3×2, 3×3, 3×4, 3×5, etc., which equal 3, 6, 9, 12, 15, etc. You can designate a minimum value to generate multiples greater than a number.