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How many liters of hydrogen are needed to react with 10 liters of nitrogen gas in the reaction forming ammonia?

How many liters of hydrogen are needed to react with 10 liters of nitrogen gas in the reaction forming ammonia?

My try:: Because we have 10 L of nitrogen gas, we have 10/22.4 moles = 0.446 moles of nitrogen gas, and thus need 0.446 * 3 = 1.338 moles of hydrogen gas. As such, we need 2.676 grams of hydrogen gas, or 2.676/0.09 = 29.8 L of hydrogen gas.

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How many moles of ammonia can be produced when 12 liters of hydrogen react with an excess of nitrogen at STP?

8 moles
Then, you can calculate how many moles of ammonia are produced when 12 moles of hydrogen reacts. Keep in mind, you also need a certain amount of nitrogen gas, but that’s not what the question is asking, so we can ignore it. Therefore, 12 moles of hydrogen makes 8 moles of ammonia.

What volume of ammonia gas in liters is produced at STP?

We know,1mol of any ideal gas at STP ( 0∘C and 1 atm ) contains 22.4L of the ideal gas. Produced ammonia is 224 L .

When nitrogen and hydrogen combine to form ammonia the ratio between the volumes of gaseous reactants and products is 1/3 2?

1 : 3: 2
In the reaction, N2 + 3H2 → 2NH3 , the ratio of volumes of nitrogen, hydrogen and ammonia is 1 : 3: 2.

How do you find the ratio of hydrogen and nitrogen in ammonia?

  1. In water , the proportion of oxygen and hydrogen by mass is : Medium.
  2. In two different experiments, the copper oxide was obtained from copper.
  3. In an experiment 3g of hydrogen was obtained.
  4. Hydrogen combines with nitrogen in a 3:14 weight ratio to form ammonia.
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How many liters of hydrogen are needed to completely react with two liters of nitrogen?

The balanced equation tells you that 3 moles or 3 liters of H2 reacts with 2 moles or 2 liters of N2 to make 2 moles or 2 liters of NH3.

What is the volume of 6.4 g of o2?

4.8 dm ^3
If 6.4 gram of oxygen occupies volume of 4.8 dm ^3 .

How many moles of ammonia are produced when 8 moles of hydrogen gas react with nitrogen gas?

As can be seen from the balanced reaction that, coefficient ratio between H2 gas and NH3 gas is 3 : 2, thus 8 mol of H2 produce ⅔ X 8 mol of NH3 = 5.33 mol of NH3.

What is the volume of 10 mole ammonia at STP?

Volume of10 Mole of Ammonia At STP=10*22.4=224 L.