How many grams of oxygen are required for the complete combustion?

Mass of oxygen required = 19.5 moles × 16 g/mol = 312 g. Hence, 312 grams of oxygen is essentially required for complete combustion of 3 moles of butane gas. So, the correct answer is “Option B”. Note: Combustion process is also known as burning.

What volume of oxygen at STP is required for the complete combustion of pentane?

According to reaction, At STP; 1 mole of acetylene that is 22.4L require 5/2 moles of oxygen that is 52×22.4 = 56L for complete combustion.

How many Litre of O2 at STP are needed to complete the combustion of 39 gram of liquid benzene?

Hence 84 litres of O2 at STP are needed to complete the combustion of 39g of liquid benzene.

How many liters of oxygen does STP have?

1 mole of any gas occupies 22.4litres.

How much O2 in gram is required for complete combustion of 4g Carbon?

Answer Expert Verified 10.67g O2 is required.

How much oxygen is needed to combust 240 grams of carbon?

So that would take about 320 grams of oxygen. But if, as usual, the result was carbon dioxide, you’d need twice as much oxygen. 20*24=480dm^3 of Oxygen is need to combust 240 grams of carbon at room temperature (rtp).

How much oxygen does it take to burn carbon monoxide?

It depends on the method of combustion. If you can burn it in a way that produces only carbon monoxide, you need one mole of oxygen (about 16 grams) for each mole of carbon (about 12 grams). So that would take about 320 grams of oxygen.

How do you calculate the moles of oxygen in a combustion reaction?

The complete combustion requires 1.527 × 1024lmolecules O2. Balance the equation. Use the molar mass of hexane to calculate the moles of hexane. Use the molar ratio of oxygen:hexane from the balanced equation to calculate the moles of oxygen. Use Avogadro’s number to calculate the molecules of oxygen.