How many five digit numbers with distinct digits are there such that in each number the digits are in descending order from left to right?

The resulting 5 digit numbers are all possible 5-digit numbers in descending order. Therefore, there are [10!/(5! 5!)] = 252 5-digit numbers in strictly descending order.

How many 5 digit numbers have the sum of their digits greater than 45?

Hence, the answer is (99,999–9,999)/2 = 45,000.

How many even 5 digit whole numbers are there?

Well the 5 digit numbers go from 10000 to 99999, meaning there are 90000 in total. We can figure out how many even numbers there are by dividing how many there are by two, which becomes 45000.

How many numbers are there in all having 5 digit?

90,000
As the name says, a 5-digit number compulsorily has 5-digits in it. The smallest 5-digit number is 10,000 and the greatest 5-digit number is 99,999. There are 90,000 five-digit numbers in all.

How many 5 digit even numbers with distinct digits can be formed using the digits?

The 5 digit even numbers can be formed out of 1, 2, 5, 5, 4 by using either 2 or 4 in the unit’s place. This can be done in 2 ways. Corresponding to each such arrangement, the remaining 4 places can be filled up by any of the remaining four digits in 4! / 2! = 12 ways.

How many 5 digits numbers are there in which the sum of the digits is even?

But, we are interested in the numbers whose sum is even so it will be half of the total five digit numbers, so the answer is 12×(9×10×10×10×10) which is 45000.

How many 5 digit numbers are there?

How Many 5-Digit Numbers are there? There are 90,000 five-digit numbers including the smallest five-digit number which is 10,000 and the largest five-digit number which is 99,999.

How many 5-digit numbers are there in strictly descending order?

The resulting 5 digit numbers are all possible 5-digit numbers in descending order. Therefore, there are [10!/ (5!5!)] = 252 5-digit numbers in strictly descending order.

What is the sum of reversed 2-digit numbers?

27 + 72 = 99. The sum of the digits in the 2-digit number determines the sum of the reversed numbers in the following way: If the sum is 6 the answer is 66 (24 + 42 = 66; 15 + 51 = 66 etc) If the sum is 8 then the sum of the reversed numbers is 88.

How do you express the first two-digit number?

You can express the first two-digit number as (10x+y) where x is the first digit and y is the second digit. Then the second two-digit number, with the digits reversed]

How do you introduce a reversed 2 digit problem?

Introduce the problem – you could do this by writing 2 reversed 2-digit numbers eg 14 and 41. Ask the students what they can tell you about the 2 numbers. If they identify that the digits have swapped places then introduce the problem.