How does the 8086 system store 20 bit address in a 16-bit register?

1 Answer. Each 20-bit physical address slot holds one 8-bit byte. A 16-bit word takes 2 consecutive address slots. Physical addresses (in original 8086) are 20 bits wide, data is (up to) 16 bits wide.

Why are there 20 address lines in 8086?

Intel 8086 uses 20 address lines and 16 data- lines. It can directly address up to 220 = 1 Mbyte of memory. It consists of a powerful instruction set, which provides operation like division and multiplication very quickly. 8086 is designed to operate in two modes, i.e., Minimum and Maximum mode.

How does the 8086 processor identify between 8 bit and 16 bit operations?

The bit size (8-bit, 16-bit, 32-bit) of a microprocecessor is determined by the hardware, specifically the width of the data bus. The Intel 8086 is a 16-bit processor because it can move 16 bits at a time over the data bus. The Intel 8088 is an 8-bit processor even though it has an identical instruction set.

How convert 16 bit address to 20 bit address explain with the help of example?

First, we shift the first address by four bits to the left: 7 2 3 A 0 which is called the base. Then, we add the the second address: 0 0 0 5 which is called the offset. The result of this operation is a new 20-bit address: 7 2 3 A 5 .

Why is 8086 a 16-bit microprocessor?

8086 processor is capable to process the 16 bit data together. means a data with 16 bit can be processed and can be send to processor in single oscillation . Therefore the data sended can be more rich and and briefed.

How is 16-bit data stored 8086?

The 8086 processor provides a 16 bit data bus. So It is capable of transferring 16 bits in one cycle but each memory location is only of a byte(8 bits), therefore we need two cycles to access 16 bits(8 bit each) from two different memory locations. The solution to this problem is Memory Banking.

What is meant by 16-bit microprocessor?

The 16 bit Microprocessor means that it has 16 address lines. A 16 bit microprocessor is having 16bit register set. It have 16 address and data lines to transfer address and data both. Hence it is 16 address lines. The maximum addresses are 2^16 means 65536.

What is meant by 16 bit address in 8086 microprocessor?

It means that in 8086, the addresses used in programs (the logical or virtual address as you call it) are 16 bits but the actual address that 8086 sends to the RAM is 20 bits. Why? Because 16 bits = 64 KB of address space where as 20 bits of address = 1 MB of memory.

What does 8086 mean?

Definition: 8086 is a 16-bit microprocessor and was designed in 1978 by Intel. Unlike, 8085, an 8086 microprocessor has 20-bit address bus. Thus, is able to access 2 20 i.e., 1 MB address in the memory. As we know that a microprocessor performs arithmetic and logic operations.

What is the difference between 16 bit and 20 bit addressing?

In the 8086, all registers are 16 bits wide, but the address bus is 20 bits wide. In order for an address of 20 bits in width to be composed in code, the CPU automatically combines the contents of two registers for all memory access (but not IO accesses, which are limited to 16 bit addressing).

What is the bit size of the address bus of processor?

The bit size of a processor is normally defined by it ALU width, which equates to its main working register width. e.g.: In both cases above the address bus is 20 bits. Of course you can have the data bus wider than the ALU to boost memory performance.