How do you print numbers without a loop in Python?

Python Program to Print Numbers in a Range (1,upper) Without Using any Loops

1. Define a recursive function.
2. Define a base case for that function that the number should be greater than zero.
3. If number is greater than 0, call the function again with the argument as the number minus 1.
4. Print the number.
5. Exit.

How to print 1 to 100 using loop in C program?

Probably we all know how to write C program to print 1 to 100 using loop. We can have a quick look of the code snippet. void print_numbers() { int i = 0; for (i = 0; i < 100; i++) { printf(“ \%d”, i+1); } } If we want to use while loop: void print_numbers() { int n = 1; while (n <= 100) printf(“ \%d”, n++); }

How to print a number from 1 to 100 using recursion?

Yes recursion is an option to do repetitive work. here is the C program to print 1 to 100 using recursion. In this example, we have a function, printnum (), to print a number of the number is less than or equal to 100. Additionally it calls itself with the next number. The function, printnum (), is called from main with 1.

How to print all numbers from 1 to 100 in Python?

The function, printnum(), will print 1 first and then will call itself by 2. This process will continue until the parameter becomes more than 100, I.e. 101. In the case the function will neither print the number nor call the function itself. The function will eventually terminates. So the function will print all numbers from 1 to 100.

Is there a way to print more than 100 printf statements?

Yes this is also a solution, you can use 100 printf statements one after another. Obviously this is not a good solution because you have to write the printf statements so many times. Even worse thing is: if you want to print 1000 numbers, you have to write the printf statement 1000 times. It is not scalable at all.