How do you find the sum of the digits in a range?
Table of Contents
- 1 How do you find the sum of the digits in a range?
- 2 How do you find the number of values in a given range divisible by a given value?
- 3 How do you know if a number is divisible by 3?
- 4 How many numbers between 1 to 300 are divisible by only 11 or only 13 but not by both?
- 5 What is the divisibility Rule 12?
- 6 What is the divisibility rule for 10?
- 7 How to count numbers in a range that are divisible?
- 8 How many prime numbers are there in the range L=5 R=10?
How do you find the sum of the digits in a range?
Algorithm to find the sum of numbers in a given range
- Input the start and end numbers.
- Initialize sum = 0.
- Repeat from i = start to and continue until i = end.
- sum = sum + i.
- Print “sum”
How do you find the number of values in a given range divisible by a given value?
14 Answers
- find the first value after x that is divisible by z . You can discard x : x_mod = x \% z; if(x_mod != 0) x += (z – x_mod);
- find the last value before y that is divisible by y . You can discard y : y -= y \% z;
- find the size of this range: if(x > y) return 0; else return (y – x) / z + 1;
How do you find the number of divisible numbers?
Therefore, a number is divisible by 2 if it has a 0, 2, 4, 6, or 8 in the ones place. For example, 54 and 2,870 are divisible by 2, but 2,221 is not divisible by 2. A number is divisible by 4 if its last two digits are divisible by 4. For example, 780, 52, and 80,744 are divisible by 4, but 7,850 is not divisible by 4.
How do you know if a number is divisible by 3?
A number is divisible by 3, if the sum of its all digits is a multiple of 3 or divisibility by 3. Sum of all the digits of 54 = 5 + 4 = 9, which is divisible by 3. Hence, 54 is divisible by 3.
How many numbers between 1 to 300 are divisible by only 11 or only 13 but not by both?
So there are (27-2) + (23-2) = 46 numbers between 1 and 300 divisible by only 11 and only 13 but not both.
What is the number divisible by 10?
A number is divisible by 10 if the last digit of the number is 0. The numbers 20, 40, 50, 170, and 990 are all divisible by 10 because their last digit is zero, 0. On the other hand, 21, 34, 127, and 468 are not divisible by 10 since they don’t end with zero.
What is the divisibility Rule 12?
Divisibility guidelines for 12: In order to know if a number is divisible by 12, you have to first check if it is divisible by 3 and 4. If it is divisible by both 3 and 4, then the number is divisible by 12.
What is the divisibility rule for 10?
The Rule for 10 In order to apply the divisibility rule for 10, the digit that is last in a number has to be 0. This works whether the number is 70, 700, or 7,000. The rule also works if the numbers do not have 0 as a middle digit such as 210, 340, and 620. All of them are divisible by 10.
How do you find the range of numbers divisible by LCM?
A naive approach is to iterate from L to R and count the numbers which are divisible by all of the array elements. An efficient approach is to find the LCM of N numbers and then count the numbers that are divisible by LCM in the range [L, R]. The numbers divisible by LCM till R are R/LCM.
How to count numbers in a range that are divisible?
Count numbers in a range that are divisible by all array elements. Given N numbers and two numbers L and R., the task is to print the count of numbers in the range [L, R] which are divisible by all numbers of the array. Examples: In range [1, 10], the numbers 4 and 8 are divisible all array elements.
How many prime numbers are there in the range L=5 R=10?
Count all the prime numbers in the range [L, R]. Input: L=1,R=10 Output: 4 Explanation: There are 4 primes in this range, which are 2,3,5 and 7. Input: L=5,R=10 Output: 2 Explanation: There are 2 primes in this range, which are 5 and 7.
How to count the number of prime numbers in a range?
Your task is to complete the function countPrimes () which takes the two integers L and R as input parameters and returns the number of prime numbers in the range [L, R]. We were unable to load Disqus.