How do you find L in a simple pendulum experiment?

A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º. The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.

How do you find the effective length of a simple pendulum?

Effective length of the pendulum: The distance L between the point of suspension and the centre of spherical bob (centre of gravity), L = l + r + e, is also called the effective length where l is the length of the string from the top of the bob to the hook, e, the length of the hook and r the radius of the bob.

What is the correct equation for the angular frequency of a pendulum with length l?

T = 2π√(L/g), f = 1/T. The angular displacement of a pendulum is represented by the equation θ = 0.32*cos(ωt) where θ is in radians and ω = 4.43 rad/s. Determine the period and length of the pendulum.

What is the shape of LT 2 graph of simple pendulum?

The graph L versus T2 is a straight line. The effective length of the second’s pendulum from the L versus T2 graph is …

What is simple pendulum class 11th?

A simple pendulum is defined as an object that has a small mass (pendulum bob), which is suspended from a wire or string having negligible mass. Simple pendulum can be set into oscillatory motion by pulling it to one side of equilibrium position and then releasing it.

How do you find the frequency of a simple pendulum?

Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s . Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz .

How do you find angular frequency?

The angular frequency ω is given by ω = 2π/T. The angular frequency is measured in radians per second. The inverse of the period is the frequency f = 1/T. The frequency f = 1/T = ω/2π of the motion gives the number of complete oscillations per unit time.

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