How do you find consecutive numbers in a list Python?

Approach :

1. Create a list.
2. Create a loop for range size – 2.
3. Check if the element is equal to the next element.
4. Again check if the next element is equal to the next element.
5. If both conditions are satisfied then print the element.

How do you find consecutive numbers in an array?

Solution

1. Find minimum and maximum element in the array.
2. Check if max-min+1==n, if elements are consecutive then this condition should meet.
3. Create a visited boolean array.
4. Iterate over the array and check. visited[arr[i]-min] is true, then return false as elements are repeated. mark the element visited.

How do you multiply consecutive numbers in Python?

As alternatives the operator module and operator.mul , you can do this:

1. a basic for-loop: list1 = [1,2,3,4,5] product = 1 for item in list1: product *= item print(product) # 120.
2. use the numpy module: from numpy import prod list1 = [1,2,3,4,5] print(prod(list1)) # 120.

How do you find consecutive elements?

1) Sort all the elements. 2) Do a linear scan of the sorted array. If the difference between the current element and the next element is anything other than 1, then return false. If all differences are 1, then return true.

How do you do consecutive numbers in Python?

How to make a code for sum of consecutive numbers

1. +7. N = int(input()) count = N x = range(1, N +1) for i in x: N = i + N print(N – count)
2. +7. Hints: ** List has a built in sum() function .
3. +2.
4. +1.
5. Sum of Consecutive numbers N=int(input ()) sum=0 for i in range(1, N+1) : sum=sum+i print(sum)

How do you find the number of consecutive zeros in Python?

Find the number of consecutive zero at the end after multiplying n numbers in Python

1. Define a function count_fact_two() . This will take n.
2. count := 0.
3. while n mod 2 is 0, do. count := count + 1.
4. return count.
5. Define a function count_fact_five() . This will take n.
6. count := 0.
7. while n mod 5 is 0, do.
8. return count.