How do you calculate aggregate ratio?
Table of Contents
- 1 How do you calculate aggregate ratio?
- 2 How much cement do I need for 1 cubic Metre of concrete?
- 3 What is the density of aggregates?
- 4 What is the ratio of fine aggregate to coarse aggregate?
- 5 What is the formula for aggregate volume of concrete?
- 6 How much aggregate is required to produce 1 CFT of concrete?
How do you calculate aggregate ratio?
The prescribed Nominal Concrete Mix Ratio of M20 grade concrete is 1:1.5:3.
- Cement = 1 Part.
- Sand = 1.5 Part.
- Aggregate = 3 Part.
- Total dry volume of ingredients required = 1.57 cu.m.
How much cement do I need for 1 cubic Metre of concrete?
Batching by volume – DIY
| Materials | 0.2 m3 concrete | 1 m3 concrete |
|---|---|---|
| cement (no. 25 kg bags) | 2.5 | 12 |
| sand (volume in m3) | 0.1 | 0.5 |
| coarse aggregate (volume in m3) | 0.2 | 1 |
| water (volume in litres) | 32 | 160 |
What is a concrete mix ratio?
In terms of the ratio for concrete, it depends on what strength you are trying to achieve, but as a general guide a standard concrete mix would be 1 part cement to 2 parts sand to 4 parts aggregates. For foundations, a mix of 1 part cement to 3 parts sand to 6 parts aggregates can be used.
What is the density of aggregates?
Most aggregates have a relative density between 2.4-2.9 with a corresponding particle density (Mass) of 2400-2900 kg / m3 (150-181 lb / ft3).
What is the ratio of fine aggregate to coarse aggregate?
Considering a concrete mix proportion (by volume) of 1:2:4. i.e., Cement: Fine aggregate (Sand) : Coarse Aggregate is in the ratio of 1:2:4 by volume.
What is the ratio of cement to aggregate in concrete mix?
Considering a concrete mix proportion (by volume) of 1:2:4 i.e., Cement: Fine aggregate (Sand) : Coarse Aggregate is in the ratio of 1:2:4 by volume. Cement required = 01 bag = 50 kg ~ 36 liters or 0.036 cum Fine Aggregate required = 2*0.036 ~ 0.07 cum = 0.072*1600 = 115 kg
What is the formula for aggregate volume of concrete?
CALCULATION FOR AGGREGATE QUANTITY Consider volume of concrete = 1m3 Dry Volume of Concrete = 1 x 1.54 = 1.54 m3 Aggregate = (3/5.5) x 1.54 = 0.84 m3 ∴ 3 is a part of cement, 5.5 is sum of ratio
How much aggregate is required to produce 1 CFT of concrete?
So 1.54 Cum of dry materials (cement, sand and aggregate) is required to produce 1 Cum of concrete Volume of Cement required = 1/ (1+2+4) X 1.54 = 1/7 X 1.54 = 0.22 Cum Volume of Sand required = 2/7 X 1.54 = 0.44 Cum or 15.53 cft Volume of Aggregate required = 4/7 X 1.54 = 0.88 Cum or 31.05 cft