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Can you find a 4 digit number which is reversed when multiplied by 9?

Can you find a 4 digit number which is reversed when multiplied by 9?

9*1089 = 9801.

What is the 4 digit number greatest 4 digit number?

9999
Answer: The greatest 4 digit number in the number system is 9999.

How do you solve Abcde 4 Edcba?

Since EDCBA is a 5-digit number, we know ABCDE is < 1/4 × 100000.

  1. ABCDE < 25000, so A is 1 or 2. But EBCDA is a multiple of 4, so it is even, so A = 2.
  2. 4 * …. E = ….
  3. We have 2BCD8 * 4 = 8DCB2. and therefore 4 × BCD + 3 = DCB.
  4. But B cannot be greater than 2, or there would be a carry, and B cannot.

How many 4 digit combinations are there?

10,000 possible combinations
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.

What is the first 4 digit number?

The smallest 4 digit number is 1000 and the greatest 4 digit number is 9999.

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When a four-digit number is multiplied by 4 its digits appear in?

When a certain four-digit number is multiplied by 4 its digits appear in reverse order. It also has the following properties. It’s first digit is a quarter of the last one. And its second digit is one less than the first. “When a four-digit number is multiplied by 4 its digits appear in reverse order.”.

What is the four digit number that is less than 2500?

The Four Digit Number is 2178. 2178 * 4 = 8712. 8712 is the reverse of 2178. Since it’s 4 Digit Number and since after multiplication also it has to be a 4 Digit Number, it’s easy to see that the Number has to be less than 2500 since 2500 * 4 = 10000.

What is the product of two numbers that multiply to 4?

A x 4 without remainder = D (2 x 4 = 8). With these two constraints, you only have two numbers multiplied by 4 that will give you 1 digit products: 1 and 2. It cannot be 3 or higher, because 3 x 4 = 12, as was shown earlier.

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How do you find 3 in a 4-digit product?

To get 3 in the one’s digit, you would have to have a remainder of 5, and 5 + 8 = 13. This would violate your 4 digit product, DCBA. Hence you rule out 3 for D, and can equate D to 8 –> D = 8.