How do you make a program reverse a number?

Let’s see a simple c example to reverse a given number.

1. #include
2. int main()
3. {
4. int n, reverse=0, rem;
5. printf(“Enter a number: “);
6. scanf(“\%d”, &n);
7. while(n!=0)
8. {

What 4-digit number times 4 equals itself backwards?

Answers. The Number is 2178.

How do you solve a 4-digit number?

Multiplying 4-Digit Numbers Quickly

1. Write down both 4-digit numbers above each other.
2. Multiply the first number by each digit of the second.
3. Carry any numbers larger than 9, and finally.
4. Add the results.

How many possibilities are there for a 4-digit code with 4 numbers?

Thanks for the A2A. If my understanding is correct, the question is referring to the standard 4-digit locks (which has numbers from 0–9). Answer: There are 9,999 different combinations in a 4-digit lock.

How do you reverse a 4 digit number in Python?

Reverse Number In Python

1. # Python Program to Reverse a Number using While loop.
2. Number = int(input(“Please Enter any Number: “))
3. Reverse = 0.
4. while(Number > 0):
5. Reminder = Number \%10.
6. Reverse = (Reverse *10) + Reminder.
7. Number = Number //10.
8. print(“\n Reverse of entered number is = \%d” \%Reverse)

How do you print in reverse order numbers?

Write a program in C to display the number in reverse order.

1. Pictorial Presentation:
2. Sample Solution:
3. C Code: #include void main(){ int num,r,sum=0,t; printf(“Input a number: “); scanf(“\%d”,#); for(t=num;num!=0;num=num/10){ r=num \% 10; sum=sum*10+r; } printf(“The number in reverse order is : \%d \n”,sum); }

What number is reversed when multiplied by 4?

To summarize, the only number that solves the puzzle is 2178. By a similar logic, we can find the six-digit number that when multiplied by 4 is equal to the original number with its digits in reverse order. Each of the intermediate carries must be 3, and so the number is 219978.

How do you reverse a 4-digit number?

Reverse of a 4-digit number: Taking the last digit every time and multiplying with 10 and dividing the number by 10 every time and repeating the loop. Btw, the above program works not just for a 4-digit number, but with any number.

How do you calculate the number reverse in a loop?

The issue is your loop size, not your logic. Assuming all your numbers are 4 digits, then int reverse = 0; int i; for( i = 0; i < 4 ; i++ ) { reverse = reverse * 10; reverse = reverse + num\%10; num = num/10; } System.out.println(reverse);

What is the formula to calculate the reverse of a number?

Assuming all your numbers are 4 digits, then int reverse = 0; int i; for( i = 0; i < 4 ; i++ ) { reverse = reverse * 10; reverse = reverse + num\%10; num = num/10; } System.out.println(reverse); will work Share Improve this answer Follow

How to reverse the digits of an integer in JavaScript?

Write a program to reverse the digits of an integer. Time Complexity: O (log (n)), where n is the input number. Time Complexity: O (log (n)) where n is the input number. We will convert the number to a string using StringBuffer after this, we will reverse that string using the reverse () method