What is the physical address space when we have 24 bit address bus Your answer should be in mega bytes?

The Intel 80286 CPU used a 24-bit addressing scheme. Each memory location was byte-addressable. This results in a total addressable space of 224 × 1 byte = 16,777,216 bytes or 16 megabytes.

How many bits are required in address for memory of 32gb in size?

A computer has 32 MB (megabytes) of memory. How many bits are needed to address any single byte in memory? The memory address space is 32 MB, or 225 (25 x 220). This means you need log2 225 or 25 bits, to address each byte.

What is 32bit OS?

A 32-bit system can access 232 different memory addresses, i.e 4 GB of RAM or physical memory ideally, it can access more than 4 GB of RAM also. A 64-bit system can access 264 different memory addresses, i.e actually 18-Quintillion bytes of RAM.

How many numbers can 32 bytes of memory have?

Range for storing integers With the two most common representations, the range is 0 through 4,294,967,295 (232 − 1) for representation as an (unsigned) binary number, and −2,147,483,648 (−231) through 2,147,483,647 (231 − 1) for representation as two’s complement.

How many address bits are required to select all byte memory locations in a 32k bytes memory?

Therefore 28 address lines ( bits) will be required to address any single word. However , to address each byte 30 bits will be required.

How many bits can a 8086 processor transfer in one cycle?

The 8086 processor provides a 16 bit data bus. So It is capable of transferring 16 bits in one cycle but each memory location is only of a byte (8 bits), therefore we need two cycles to access 16 bits (8 bit each) from two different memory locations.

How many things can be added to a 16-bit address?

One address addresses one something. So 16 bits of address can address 2 16 something s. In the case of memory organised in bytes, this is 64KB (kilobytes). If memory were organised in bits, this would be 64Kb (kilobits).

How many bytes can a 64K address line address?

Sixteen address lines will address 64K bytes. If you count in binary (which computers always do) and limit yourself to 16 binary columns, you can count from 0 to 65,535. (The colloquial ‘‘64K’’ is shorthand for the number 66,536.)

How many bytes is 65536 bytes?

Using 16 bits, you can write 65536 addresses (from 0 to 65535, that’s 65536 different addresses), and address 65536 bytes. 65536 bytes is 64kB. In computer science, b is bit, B is byte. The byte is the smallest amount of memory you can address. The question “what is k?”.