What is the maximum height reach by the ball?
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What is the maximum height reach by the ball?
Thus, the greatest height reached by the ball is 20.39m . Here, t1 represent the time when the ball is 15m above the ground. Substitute all the known values in the above formula. From the above calculations, the most suitable when the ball is 15m above the ground would be 3.09s .
What happens to the velocity of a ball as it is dropped off a cliff?
When the ball comes back down to ground level it has exactly the same speed as when it was thrown up, but its velocity is reversed. This is an example of the law of conservation of energy.
How fast should a ball be thrown to reach a maximum height of 19 m?
The velocity of the ball at maximum height (v) = 0. g = 9.8m/s^2 Let us consider the maximum height as H. Consider the formula, 2gH = v^2– u^2 2 × (- 9.8) × H = 0 – (19)^2 – 19.6 H = – 361 H = 18.418 m. Therefore, The ball will travel a maximum height of 18.418m upwards before it starts to reverse its direction.
Is a ball thrown upward considered a free falling body?
Freefall is a special case of motion with constant acceleration, because acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity. For example, when a ball is thrown up in the air, the ball’s velocity is initially upward.
How high can a ball fall from the top of Tower?
A ball is allowed to fall from the top of a tower 200 m high , At the same instant another ball is thrown vertically upward from the bottom of a tower with a velocity of 40 m per sec. When and where the two ball meets.?? Let us assume that the two balls meet at a height ‘h’ after time ‘t’ above the ground.
What is the initial velocity of the body thrown from the tower?
A body is thrown horizontally from the top of a tower of height 5 m . It touches the ground at a distance of 10 m from the foot of the tower. The initial velocity of the body is ( g = 10 ms^-2 ) A body is thrown horizontally from the top of a tower of height 5 m. It touches the ground at a distance of 10 m from the foot of the tower.
What is the height of the ball before and after impact?
A ball is allowed to fall from a height of 10 m. If there is 40\% loss of energy due to impact, then after one impact ball will go upto: Note that hereafter one impact ball looses 40\% energy and is left with 60\% energy. Thus by conservation of energy, are the height of ball before and after impact.