How much mole oxygen will complete combustion of ethanol?

So for every mole of ethanol we need three moles of oxygen.

How many moles of oxygen are needed to completely react with 3.0 moles of ethanol?

So 3 moles of O2 react with 1 mole of ethanol, so 9 moles of O2 will react with 3 moles of C2H5OH (ethanol).

How many moles of oxygen are consumed during the complete combustion of one mole of ethanol?

3 moles
1 mole of ethanol reacts with 3 moles of oxygen.

How do you calculate the amount of oxygen needed for complete combustion?

Thus for 1 mole methane we need 2 mole of oxygen for complete combustion. Hence 0.5 moles of oxygen will occupy 22.4 L x 0.5 = 11.2 L. 11.2 L of oxygen is required for complete combustion of 0.25 mole methane at STP.

What does 5 moles of water weigh?

From this you can see that 5 moles of hydrogen gas would react with 2.5 of the available 3 moles of oxygen gas, to form 5 moles of water. The molar mass of water is 18 g/mol, so you would end up with 5 x 18 = 90 g of water.

How many grams of h3po4 are produced when 10.0 moles of water react with an excess of P4O10?

Thus, if the reaction goes to completion, there will be a yield of 653 grams of phosphoric acid .

How many moles of oxygen are consumed?

If, or when, hydrogen reacts with oxygen, two molecules of hydrogen and one molecule of oxygen are consumed for every two molecules of water produced. If, or when, hydrogen reacts with oxygen, two moles of hydrogen and one mole of oxygen are consumed for every two moles of water produced.

How many moles of oxygen are required for complete combustion of ethane?

To calculate for the moles oxygen required, we use the ratio based on the balanced equation as shown. moles oxygen required = 2.5 mol ethane (7 mol oxygen / 2 mol ethane) = 8.75 mole Hence, 75.0 g ethane needs 8.75 moles oxygen for complete combustion.

How many moles of oxygen are needed to burn 1 mole C3H8?

C3H8 + 5O2 → 3CO2 + 4H2O From above balanced equation, it’s clear that we need 5 moles of oxygen to burn 1 mole of C3H8 So, to burn 10.0 moles of C3H8 we need 50 moles of oxygen Mass of 50 moles of oxygen = 50moles × 32 g mol = 1600 g = 1.6 kg

How many moles of O2 react with C2H5OH?

According to the aforementioned equation, we can use the mole ratio between the ethanol (C2H5OH) and the oxygen (O2) as follows: Therefore it will require 6.66 moles of O2 to completely react with 2.2 moles of C2H5OH.

What is the volume of one mole of oxygen at 2 STP?

Avogadro’s law predicts that at STP the volume of one mole of oxygen gas is 22.4 liters. Computing for its volume at 2 STP means that its temperature in Kelvin is twice the former temperature. Its pressure must be twice the former pressure or at 2 atmospheres. The volume can be calculated by using the combined gas laws.