How do I print a pointer address?

Printing pointers. You can print a pointer value using printf with the \%p format specifier. To do so, you should convert the pointer to type void * first using a cast (see below for void * pointers), although on machines that don’t have different representations for different pointer types, this may not be necessary.

Do pointers have an address?

The main feature of a pointer is its two-part nature. The pointer itself holds an address. The pointer also points to a value of a specific type – the value at the address the point holds.

What is the address of a pointer in C++?

In C++, a pointer refers to a variable that holds the address of another variable. Like regular variables, pointers have a data type. For example, a pointer of type integer can hold the address of a variable of type integer. A pointer of character type can hold the address of a variable of character type.

How do I print a pointer address without printf?

If you want to print the value of a pointer without using the format \%p specifier, you can cast the pointer to an integer that has the same size and then print the integer value. int x; Serial.

How do you print a hex pointer?

For printing a data-pointer, there is \%p which can print void-pointers (type void* , the conversion is not optional), which will normally print it with hexadecimal notation.

How do you assign a pointer to an address?

You need to initialize a pointer by assigning it a valid address. This is normally done via the address-of operator (&). The address-of operator (&) operates on a variable, and returns the address of the variable. For example, if number is an int variable, &number returns the address of the variable number.

What is the address of a pointer variable?

As just seen, a variable which stores the address of another variable is called a pointer. Pointers are said to “point to” the variable whose address they store. An interesting property of pointers is that they can be used to access the variable they point to directly.

How do you address a pointer?

To access address of a variable to a pointer, we use the unary operator & (ampersand) that returns the address of that variable. For example &x gives us address of variable x.

What is Uintptr_t?

uintptr_t is an unsigned integer type that is capable of storing a data pointer. Which typically means that it’s the same size as a pointer. It is optionally defined in C++11 and later standards.

How do I print a string pointer?

First of all, we are reading string in str and then assigning the base address of str to the character pointer ptr by using ptr=str or it can also be done by using ptr = &str[0]. And, finally we are printing the string character by character until NULL not found. Characters are printing by the pointer *ptr.

How to print the address in pointer to pointer?

To print address in pointer to pointer: You can always verify with debugger, if you are on linux use ddd and display memory, or just plain gdb, you will see the memory address so you can compare with the values in your pointers. What you have is correct. Of course, you’ll see that emp1 and item1 have the same pointer value.

How do you get the value of a pointer in C++?

To access the value that a pointer points to, you have to use the indirection operator *. To print the pointer itself, just access the pointer variable with no operator. And to get the address of the pointer variable, use the &operator.

How to print the address in C++?

or, only in C++11, you can do: auto pp = std::addressof (p); To print the address in C, most compilers support \%p, so you can simply do: printf (“addr: \%p”, pp);

Why can’t I cast pointers to (void*) in printf arguments?

It’s just a quirk of the language. Normally, it’s considered poor style to unnecessarily cast pointers to (void*). Here, however, you need the casts to (void*) on the printf arguments because printf is variadic. The prototype doesn’t tell the compiler what type to convert the pointers to at the call site.