What is the maximum value of COSX sinx?

Hence the maximum value of sinx-cosx is $\sqrt{2}$.

What is COSX sinx?

The cotangent of x is defined to be the cosine of x divided by the sine of x: cot x = cos x sin x .

What is the minimum value of 3 COSX 4sinx 8?

3
Hence, the minimum value of 3cosx+4sinx+8 is 3.

What is the period of sinx COSX?

2π
Periodicity: sinx, cosx have period 2π; tanx, cotx have period π Symmetry: cos is an even function, sin, tan, cot are odd.

What is the smallest value of Sinx?

−1
The minimum value of sinx is −1. At x = 270°, sinx = −1.

What is the minimum value of cos COSX?

Note: Cosine is a decreasing function from o to $\pi$. It has maximum value 1 when $x={{0}^{\circ }}$ and minimum value -1 when $x={\pi }$. So we can also say \[\cos (\cos x)\] will have a maximum value when cos(x) has value 0.

Is sinx * COSX periodic?

Periodicity: sinx, cosx have period 2π; tanx, cotx have period π Symmetry: cos is an even function, sin, tan, cot are odd.

What is the minimum value of SiNx and Y?

The minimum value of sinx is -1 and the minimum value of y is -√2. Was this answer helpful? Thank you. Your Feedback will Help us Serve you better.

How to find the value of sin2x/2?

Multiply by 2 in numerator and denominator . 2sinx cosx / 2 Sin2x /2 (using sin2A = 2sinAcosA) (Value of sin lies between -1 to +1) -1<_ sin2x <_ +1 Divide by 2 -1/2 <_ sin2x/2 <_ +1/2 Therefore minimum value = -1/2 Maximum value =+1/2 Still looking for help?

What is the exact value of sin( π2) sin(π)?

The exact value of sin ( π 2) sin ( π 2) is 1 1. Multiply − 1 – 1 by 1 1. Multiply − 1 – 1 by − 1 – 1. x = 3π 2 x = 3 π 2 is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test. These are the local extrema for f (x) = sin(x) f ( x) = sin ( x).

What is the exact value of arccos(0) in cosine?

The exact value of arccos(0) arccos ( 0) is π 2 π 2. The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from 2π 2 π to find the solution in the fourth quadrant. Simplify 2π− π 2 2 π – π 2. Tap for more steps…