What is the value of x if sin x is equal to cos X?

$ \sin x = \cos x $ and we need to find the value of angle x in degrees. It is given that the angle is acute i.e. less than 90° which is also true for the angle obtained. So, the correct answer is “ 45° ”. Thus, we get the value of x as 45° by following every method.

Is it ever possible for sin x cos x explain?

From the unit circle we see that sin x and cos x can only have the same value in two places, in x = /4 and x = 5 /4 (45° and 225°). The equation sin x = cos x can also be solved by dividing through by cos x. If we put k = 0 and k = 1 we get the solutions /4 (45°) and /4 + = 5 /4 (45°+ 180°= 225°).

What is the greatest value of sin x into COS X?

Hence the maximum value of sinx-cosx is $\sqrt{2}$.

What is the value of sin x – cos x at 45?

The range of variable ‘x’ is between 0 and 45 including these points. When x is 0, sin x is 0 and cos x is 1. So, sin x – cos x is -1 (negative). When x tends from 0 to 45, value of sin x increases and value of cos x decreases. At x =45° , sin x and cos x are both equal, ie, 1/√2. So the value of sin x – cos x is 0 at x = 45.

How to find the value of sin 45 using negative angles?

We can use our negative angle identities to find this. The negative angle identity involving the sine function gives that sin (- x) = -sin ( x ). We are given that sin (45) = √2 / 2. Therefore, -sin (45) = -√2 / 2.

How do you find the value of the cosine function?

(= 1.57 = 90∘). The value of the cosine function is positive in the first and fourth quadrants (remember, for this diagram we are measuring the angle from the vertical axis), and it’s negative in the 2nd and 3rd quadrants. Now let’s have a look at the graph of the simplest cosine curve, y = cos x (= 1 cos x).

What is sin 45 degrees equal to?

45 degrees or pi/4 radians. sin (45 degrees) = cos (45 degrees) = 1/sqrt (2). If you think about it at 45 degrees the x distance (cosine) and the y distance (sine) of the right triangle would be the same. If the hypotensue is equal to 1 then the x and y distance will have to be a little less than on each.