What is the value of sinAcosA?

Sin A x Cos a = SinACosA. At 0 degrees, the value is 0. At 30 degrees, the value is 0.4330 approximately.

What is the maximum value of sinAcosA?

maximum value of sinAcosA. If `tan A=3/4`, then `sinAcosA = 12/25`.

What is sinAcosA?

sinA×cosA=1/2 ×sin2A. =sinAsin(pi/2-2A)

What is the formula of Sinacosa?

= cosA cosB + sinA sinB sin2 A + cos2 A = 1, sin 2A = 2 sinA cosA cos 2A = 2 cos2 A − 1=1 − 2 sin2 A 2 sinA cosB = sin(A + B) + sin(A − B) 2 cosA sinB = sin(A + B) − sin(A − B)

What is the minimum value of sin a 0 90?

As sin 90 is equal to zero.

What is the minimum in math?

minimum, in mathematics, point at which the value of a function is less than or equal to the value at any nearby point (local minimum) or at any point (absolute minimum); see extremum.

What is Sina * SINB?

Sina Sinb is the trigonometry identity for two different angles whose sum and difference are known. The sina sinb formula is half the difference of the cosines of the difference and sum of the angles a and b, that is, sina sinb = (1/2)[cos(a – b) – cos(a + b)].

How to find min value of sin θ + cosec θ?

Sometimes, we come across a special case of trigonometric identities like to find min. value of sin θ + cosec θ or tan θ + cot θ or cos2 θ + sec2 θ etc. These identities have one thing in common i.e., the first trigonometric term is opposite of the second term or vice-versa ( tan θ = 1/ cot θ , sin θ = 1/ cosec θ , cos2 θ = 1/ sec2 θ ).

What is the minimum and maximum value of sin sin x?

Minimum and maximum value of Sin Sin x is. Do not exist-1, 1; Sin -1 , Sin +1 – Sin 1 , Sin 1; We know that, -1 ≤ Sin nx ≤ 1 = Sin (-1) ≤ Sin x ≤ Sin (1) = – Sin 1 ≤ Sin x ≤ Sin 1 ; [Sin(-θ) is same as – Sin θ ] Therefore, Minimum value is –Sin 1 and maximum is Sin 1 ( correct answer D) The key to success is Practice!

What is the maximum and minimum point of sin 45 -cos45?

When the derivative is equal to zero, you are at either a maximum or a minimum. A = 45 degrees. If the second derivative at that point is positive, you are at a minimum point. If the second derivative at that point is negative, you are at a maximum point. -sin45 -cos45 = -2^½ which is negative, so we are at a maximum point.