What is the address space in a system with 32 bit addresses?

4 gigabytes
In 32-bit Windows, the total available virtual address space is 2^32 bytes (4 gigabytes).

What will be HE page directory size for a 32 bit system with 4KB page size?

Consider a system with a 32-bit logical address space. If the page size in such a system is 4 KB (2^12), then a page table may consist of up to 1 million entries (2^32/2^12). Assuming that each entry consists of 4 bytes, each process may need up to 4 MB of physical address space for the page table alone.

How many bits do we need to specify the page number in the 32 bit logical address if the page size is 4KB?

20 bits
With 32 bit physical addresses and 4KB pages the frame number only requires 20 bits.

What is the minimum number of pages that need to be allocated for a two level page table?

minimum number of pages = 1 (for top-level page table) + 1 * 4 (for second-level page table) = 5 Note that a second-level page table needs 4 pages.

What is the limit of the virtual address space size for a processor with a 32-bit word size?

A 32-bit word size limits the virtual address space to 4 gigabytes, that is, just over 4 x 10^9 bytes. Is my understanding correct that it’s the number of possible addresses, not the total memory size?

What is system address space?

The range of virtual addresses that the operating system assigns to a user or separately running program is called an address space. This is the area of contiguous virtual addresses available for executing instructions and storing data.

How many entries does a conventional page table contain Assuming a 32 bit logical address with an 8 KB page size?

A 32-bit logical address with 8 KB page size will have 1,000,000 entries in a conventional page table. Hierarchical page tables are appropriate for 64-bit architectures. Inverted page tables require each process to have its own page table.

What is page size in operating system?

With computers, page size refers to the size of a page, which is a block of stored memory. Page size affects the amount of memory needed and space used when running programs. This feature allows it to calculate the most efficient use of memory while running that program.

How many 4KB pages could be represented in an address space that uses 32 bit addresses?

Assuming a 4GB (2^32 byte) virtual and physical address space and a page size of 4kB (2^12 bytes), we see that the the 2^32 byte address space must be split into 2^20 pages.

How many bits of an address are used for the page offset?

The last 12 bits of the virtual address are the offset in a page, varying from 0 to 4095. So the page size is 4096, that is, 4K.

How many bits are used for page number and how many bits are used for offset?

Show your work for possible partial credit. 20 of 64 bits are used for the offset, leaving 44 bits for page numbers. Each level of page tables will require a 16 bit page number (because 216 is the maximum size of each page table).