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How many liters of hydrogen are needed to react with 10 liters of nitrogen gas in the reaction forming ammonia?

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How many liters of hydrogen are needed to react with 10 liters of nitrogen gas in the reaction forming ammonia?

My try:: Because we have 10 L of nitrogen gas, we have 10/22.4 moles = 0.446 moles of nitrogen gas, and thus need 0.446 * 3 = 1.338 moles of hydrogen gas. As such, we need 2.676 grams of hydrogen gas, or 2.676/0.09 = 29.8 L of hydrogen gas.

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How many moles of ammonia can be produced when 12 liters of hydrogen react with an excess of nitrogen at STP?

8 moles
Then, you can calculate how many moles of ammonia are produced when 12 moles of hydrogen reacts. Keep in mind, you also need a certain amount of nitrogen gas, but that’s not what the question is asking, so we can ignore it. Therefore, 12 moles of hydrogen makes 8 moles of ammonia.

What volume of ammonia gas in liters is produced at STP?

We know,1mol of any ideal gas at STP ( 0∘C and 1 atm ) contains 22.4L of the ideal gas. Produced ammonia is 224 L .

When nitrogen and hydrogen combine to form ammonia the ratio between the volumes of gaseous reactants and products is 1/3 2?

1 : 3: 2
In the reaction, N2 + 3H2 → 2NH3 , the ratio of volumes of nitrogen, hydrogen and ammonia is 1 : 3: 2.

How do you find the ratio of hydrogen and nitrogen in ammonia?

  1. In water , the proportion of oxygen and hydrogen by mass is : Medium.
  2. In two different experiments, the copper oxide was obtained from copper.
  3. In an experiment 3g of hydrogen was obtained.
  4. Hydrogen combines with nitrogen in a 3:14 weight ratio to form ammonia.
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How many liters of hydrogen are needed to completely react with two liters of nitrogen?

The balanced equation tells you that 3 moles or 3 liters of H2 reacts with 2 moles or 2 liters of N2 to make 2 moles or 2 liters of NH3.

What is the volume of 6.4 g of o2?

4.8 dm ^3
If 6.4 gram of oxygen occupies volume of 4.8 dm ^3 .

How many moles of ammonia are produced when 8 moles of hydrogen gas react with nitrogen gas?

As can be seen from the balanced reaction that, coefficient ratio between H2 gas and NH3 gas is 3 : 2, thus 8 mol of H2 produce ⅔ X 8 mol of NH3 = 5.33 mol of NH3.

What is the volume of 10 mole ammonia at STP?

Volume of10 Mole of Ammonia At STP=10*22.4=224 L.