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How many ways can a party of 4 men and 4 women be seated at a circular table so that no two women are adjacent?

How many ways can a party of 4 men and 4 women be seated at a circular table so that no two women are adjacent?

∴ the required number of ways = (6×24)=144.

How many ways can 3 men and 3 women be seated at around table such that no two men sit together?

Three men can be seated first at the round table in 2! = 2 ways. Then the three women can be seated in 3 gaps in 3! = 6 ways.

How many ways can a group of 4 men and 3 women be selected?

Combinations of 4 men and 3 women that include neither D nor A = 5*35 = 175.

How many ways can 4 men and 4 women?

of ways = 6 × 24 = 144 ways.

How many different way can I arrange 3 men and 3 women around a round table when no ordering is specified?

But we only 2 3s, so you cannot have number 333. 333 is the only number where you use 3 threes. So you can have 26 possible combinations.

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How many ways can the three women be arranged among themselves?

The three woman can be arranged among themselves in 3! ways. According to Fundamental principle of counting, Total No of ways in which 4 men & 3 women can be seated around a round table such that women always sit together is 4! x 3! = 144 ways Since all women sit together, let us treat them as a single unit.

How many places are there between the men and the women?

Now there are 4 places between the men and three women are to be seated between the men. That can be done in 4 P 3 ways. Again you get 144 arrangements. Hope it helps. If the women have to sit together, they from a group which can be arranged in 3! possibilities.

How many women can be arranged in 4p3 ways?

Now there are 4 places between the men and three women are to be seated between the men. That can be done in 4P3 ways. Again you get 144 arrangements. , Good at maths. Case i:All women sit together. Women can be arranged in 3!= 6 ways. Now consider all women as a man. So we now have 5 men .

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How many different arrangements can be made for 4 men?

The 4 men can be seated in the remaining 4 places in 4! ways. Therefore, there are 144 arrangements. For case 2: First fix the men in circular arrangement, which can be done in 3! following from the formula ( n − 1)! . Now there are 4 places between the men and three women are to be seated between the men. That can be done in 4 P 3 ways.