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How will the fringe pattern change if the screen is moved away from the slits?

How will the fringe pattern change if the screen is moved away from the slits?

d = distance between the slits. $\lambda $ = wavelength. $\left( a \right)$ When the screen is moved away from the plane of the slits the distance between the slits is increased from equation (1). Therefore if D is increased, and it is given that remaining parameters remain same so bandwidth (B.W) is increased.

What is the effect on the interference fringes when the source slit is moved closer to the double slit plane?

If the source slit is moved towards or closer to the double slit plane then this condition is not satisfied. The value of S decreases and the interference fringes will overlap on one another. Due to this interference pattern will be less sharp and have low intensity.

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What is the effect on the interference fringes if the width of the source slit is increased?

As the source slit width increase, fringe pattern gets less and less sharp. When the source slit is so wide the above condition does not satisfied and the interference pattern disappears.

What will be the effect on fringe width?

(a) When screen is moved away, D increases. therefore width of the fringes increases. However, angular separation (λ/d) remains the same. ∴ β decreases i.e., fringe width decreases.

What is the effect on the interference pattern observed in a Young’s double slit experiment in the following cases I screen is moved away from the plane of the slits?

(i) As fringe width β=λDd, hence β∝D. Thus, as the screen is moved away from the plane of the slits, the fringe width increases. (ii) As fringe width β∝1d. Thus, as the separation between the slits is increased, the fringe width decreases.

What is the effect on the interference fringes?

( c) When separation between slits is increased, d increases. Therefore fringe width β decreases. As source slit is brought closer to double slit plane, S decreases, teh interference pattern gets less and less sharp. When the source is too close, the fringe separation remains fixed.

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What is the effect on interference fringes when?

If the source slit width increases, fringe pattern gets less sharp or faint. When the source slit is made wide which does not fullfil the above condition and interference pattern not visible.

What is the effect on the fringe width?

Hence, if the distance between the slits is reduced then the width of the fringes increases. In that case, fewer nodal regions are produced on the screen and the fringes will become wider but less in number.

How does the fringe width of interference fringes changes with increase in distance between the slits?

( c) When separation between slits is increased, d increases. Therefore fringe width β decreases. As source slit is brought closer to double slit plane, S decreases, teh interference pattern gets less and less sharp.

What will be effect on fringe width I when screen moved away from the plane of slit II separation between the slit is increased III wave length of light increase?

What are the factors on which fringe width of interference fringes depend?

Answer: The wavelength of light, distance between the slits and the screen or slit separation.

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What is fringe width in young’s double slit experiment?

Distance between two adjacent bright (or dark) fringes is called the fringe width. If the apparatus of Young’s double slit experiment is immersed in a liquid of refractive index (μ), then the wavelength of light and fringe width decreases ‘μ’ times.

What happens when white light is used in a double slit experiment?

If a white light is used in the double slit experiment, the different colours will be split up on the viewing screen according to their wavelengths. The violet end of the spectrum (with the shortest wavelengths) is closer to the central fringe, with the other colours being further away in order.

How do you find the dark fringe of a double slit?

Similarly, the expression for a dark fringe in Young’s double slit experiment can be found by setting the path difference as: Δl = (n+12)λ. This simplifies to yn = (n+12)λDd. Note that these expressions require that θ be very small. Hence yD needs to be very small. This implies D should be very large and y should be small.

How did young’s double-slit experiment help in understanding wave theory of light?

Young’s double-slit experiment helped in understanding the wave theory of light which is explained with the help of a diagram. A screen or photodetector is placed at a large distance ’D’ away from the slits as shown.