What is the size of the memory for a 24-bit address?

The size of the address bus determines how much memory the CPU can address directly. For example, a 20-bit address bus can access up to one megabyte (1MB); 24 bits reaches 16MB, and 32 bits can handle four gigabytes (GB).

What is the maximum size of addressable primary memory on a 24-bit machine?

At any rate, with 24-bit addresses, we’d have 224=16777216=16M possible addresses, hence that many possible chunks. If each chunk was a byte that would mean that the total addressable memory would be 16777216 bytes, or 16MB.

What is the physical address space when we have 24-bit address bus Your answer should be in mega bytes?

The Intel 80286 CPU used a 24-bit addressing scheme. Each memory location was byte-addressable. This results in a total addressable space of 224 × 1 byte = 16,777,216 bytes or 16 megabytes.

What is the maximum memory addressable using 28 address lines?

What is the capacity of the memory? The DRAM chip has 16 rows and 12 columns, for a total of 28 address lines. 228 = 268,435,456 memory locations. Also, 228 = 28 × 220 = 256 × 220 = 256 M.

What is bit capacity of microprocessor?

Historically, the processor classification in bits (8, 16, 32, 64 and so on) gives the size of the ALU. This means that an 8 bit processor can handle 8 bit of data in one cycle, a 16 bit processor 16 bit data and so on. This does not mean that they can’t handle larger data, it just takes longer.

What is 24-bit addressing?

24-bit addressing involves computers that can locate memory addresses that are 24-bits (3 bytes) wide, allowing for a theoretical maximum of 16 megabytes of memory, though logic board configurations may add other limitations.

What is the maximum addressable memory limit for a 64-bit processor?

A 64-bit register can theoretically reference 18,446,744,073,709,551,616 bytes, or 17,179,869,184 gigabytes (16 exabytes) of memory.

What is the maximum directly addressable memory capacity of 64-bit microprocessor?

In principle, a 64-bit microprocessor can address 16 EiB (16 × 10246 = 264 = 18,446,744,073,709,551,616 bytes, or about 18.4 exabytes) of memory. However, not all instruction sets, and not all processors implementing those instruction sets, support a full 64-bit virtual or physical address space.

How many memory locations can be addressed by a microprocessor that uses 24-bit addressing?

A 1-bit address bus can address up to two locations (that is 0 and 1). A 2-bit address bus can address 22 or 4 locations (that is 00, 01, 10 and 11). A 20-bit address bus can address up to 220 addresses (1 MB). A 24-bit address bus can address up to 16 MB.

What is memory addressing capacity for 32 address lines microprocessors?

32 Address lines means 2^32 possible addresses, and a data bus 16 bits wide accommodates 2 bytes, so that means that in terms of bytes, the memory space is 2^33, or 8,589,934,592 bytes. This is otherwise known as 8GB.

What will be extended memory size of a processor having 32 bit address lines?

For example, an 8-bit-byte-addressable machine with a 20-bit address bus (e.g. Intel 8086) can address 220 (1,048,576) memory locations, or one MiB of memory, while a 32-bit bus (e.g. Intel 80386) addresses 232 (4,294,967,296) locations, or a 4 GiB address space.

What are the three internal buses associated with a processor?

There are three internal buses associated with processors: the data bus, address bus, and control bus. Data moving in and out of the data bus is bi-directional, since the processor reads and writes data, however, the others are uni-directional, since the processor always determines when and what it will read from or write to.

What is the size of the addressable memory in a processor?

Most modern processors do not address memory at the granularity of single bits but limit the size of the smallest chunk of memory that can be accessed to an 8-bit byte. This is called byte-addressable memory. With byte-addressable memory, a 24-bit immediate could directly address any of 2 24 bytes, i.e.,…

How many address lines are there in a 64 bit memory?

So basically 22 address lines. With DRAM-DDR, some of these are CPU-internal (as RAM has a data bus of 64 bits currently, which is 8=2^3 bytes). More exactly, 3 are CPU-internal which leave 19 external.

What is the size of 16 address lines of RAM?

If static RAM or flash, the size of that memory will be 2^ [number of address lines]. For example, 16 address lines would be 64k bytes, assuming 8 data lined. For dynamic RAM, you multiply the number of address lines by 2. The formula is: Also, in the past, DRAM chips were 1 bit.